Skip to content
Related Articles

Related Articles

Write a bash script to print a particular line from a file

View Discussion
Improve Article
Save Article
  • Difficulty Level : Easy
  • Last Updated : 26 Sep, 2017

Given a file, name file.txt, out task is to write a bash script which print particular line from a file.

Content of file.txt:


Syntax in Bash Script

  1. awk :
    $>awk '{if(NR==LINE_NUMBER) print $0}' file.txt
  2. sed :
    $>sed -n LINE_NUMBERp file.txt
  3. head :
    $>head -n LINE_NUMBER file.txt | tail -n + LINE_NUMBER
    Here LINE_NUMBER is, 
    which line number you want to print


    Print a line from single file

    To print 4th line from the file then we will run following commands. The output of following lines will be “articles”.

    1. awk :
      $>awk '{if(NR==4) print $0}' file.txt
    2. sed :
      $>sed -n 4p file.txt 
    3. head :
      $>head -n 4 file.txt | tail -n + 4

    Print a line from multiple files

    Suppose we have two files, file1.txt and file2.txt, We can use the above commands and print particular line from multiple files by ‘&’.

    1. awk:
      $>awk '{if(NR==4) print $0}' file1.txt & awk '{if(NR==4) print $0}' file2.txt
    2. sed:
      $>sed -n 4p file1.txt & sed -n 4p file2.txt
    3. head:
      $>head -n 4 file1.txt | tail -n + 4 & head -n 4 file2.txt | tail -n + 4

    This article is contributed by Sahil Rajput. If you like GeeksforGeeks and would like to contribute, you can also write an article using or mail your article to See your article appearing on the GeeksforGeeks main page and help other Geeks.

    Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

    My Personal Notes arrow_drop_up
Recommended Articles
Page :

Start Your Coding Journey Now!