1. If num is positive then add 0.5.
2. Else subtract 0.5.
3. Type cast the result to int and return.
num = 1.67, (int) num + 0.5 = (int)2.17 = 2
num = -1.67, (int) num – 0.5 = -(int)2.17 = -2
Time complexity: O(1)
Space complexity: O(1)
Now try rounding for a given precision. i.e., if given precision is 2 then function should return 1.63 for 1.63322 and -1.63 for 1.6332.
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