wmemmove() function in c++

The wmemmove() function is defined in cwchar.h header file. The wmemmove() function copies a specified number of wide characters from source to the destination.

Syntax:

wchar_t* wmemmove(wchar_t* dest, const wchar_t* src, size_t n);

Parameters: This method accepts the following parameters:

  • dest: specifies the pointer to the destination array.
  • src specifies the pointer to the source array.
  • n: Number of wide characters to copy from src to dest.

Returns: The wmemmove() function returns the modified destination.

Below program illustrate the above function:-

Example:-

filter_none

edit
close

play_arrow

link
brightness_4
code

// c++ program to demonstrate
// example of wmemmove() function.
  
  
#include <bits/stdc++.h>
using namespace std;
  
int main()
{
  
    // maximum length of the destination string
    wchar_t dest[30];
  
    // maximum length of the source string
    wchar_t src[30];
  
    // initialize the destination string
    wcscpy(dest, L"A computer science portal for geeks");
  
    wprintf(L"Destination: %ls\n", dest);
  
    // initialize the source string
    wcscpy(src, L"geeksforgeeks");
  
    wprintf(L"Source: %ls\n", src);
  
    wmemmove(dest+2, src+3, 5);
  
    wprintf(L"After modication, destinstion: %ls\n", dest);
  
    return 0;
}

chevron_right


Output:

Destination: A computer science portal for geeks
Source: geeksforgeeks
After modication, destinstion: A ksforter science portal for gegeeksforgeeks


My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.




Article Tags :
Practice Tags :


Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.