Which term of the progression 4, 9, 14, 19 is 109?
Problem Statement: Which term of the progression 4,9, 14, 19 is 109
Solution:
Given:
The formula to find the nth term of the Arithmetic Progression:
an= a + (n – 1) d.
here,
an= 109, a= 4, and d= 5 and we need to find the n.
Therefore:
109 = 4+(n-1)×5
105/5 = (n-1)
n = 22
Hence, 109 is the 22nd term of the Arithmetic Progression.
Formula for n term of AP
Formula for the nth term of the Arithmetic Progression is given by:
an= a + (n – 1)d
where:
- a = first term
- d = common difference
Similar Questions
Question 1: Write the A.P. when the first term is 20 and the common difference is 2.
Solution:
Given:
Let us consider, the Arithmetic Progression series be a1, a2, a3, a4, a5 …
a1 = a = 20
a2 = a1 + d = 20 + 2 = 22
a3 = a2 + d = 22 + 2 = 24
a4 = a3 + d = 24+ 2 = 26
And so on…
Therefore, the A.P. is 20, 22, 24,26…
Question 2: Find the 13th term of an AP if the first term is 6 and the common difference is 3.
Solution:
Given:
Formula to find the nth term of the Arithmetic Progression:
an= a + (n – 1)d.
here,
We need to find the 13th term.
Therefore:
an= 6 + ( 13- 1 )3
an= 42
Hence, the 13th term is 42.
Last Updated :
18 Mar, 2024
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