# Which figure encloses more area: a square of side 2 cm a rectangle of side 3 cm and 2 cm a triangle of side 4 cm and height 2 cm?

Square is a closed two-dimensional figure with four sides and four corners. The length of all four sides is equal and parallel to each other.

A square is a quadrilateral in which:

- The opposite sides are parallel.
- All four sides are equal.
- All angles measure 90°.

**Area of a Square**

Area of a square is the space enclosed within its boundary. It is given by the product of any of its two sides and denoted in sq. units. By formula, we have,

Area of a square = Side × Side

Let us assume the side of the square to be equal to S.

Therefore,

Area = S

^{2}.

**Area of a triangle **

A triangle is a two dimensional-figure enclosed within three sides, which may or may not be of equivalent length. The area is considered to be the space contained within the three sides. The height of the triangle connects the apex to the mid point of the base of the third side. Now.

Let us assume h to be the height and b the base of the triangle,

Therefore,

Area = 1/2 × base × height

= 1/2 × b × h

**Area of a rectangle**

The area of a rectangle is the space enclosed within its boundary. It is given by the product of any of its length and breadth and denoted in sq. units. By formula, we have,

Area of a rectangle = Length x Breadth

Let us assume the length of the rectangle to be equal to l and b to be breadth.

Therefore,

Area = length × breadth.

### Which figure encloses more area: a square of side 2 cm a rectangle of side 3 cm and 2 cm a triangle of side 4 cm and height 2 cm?

**Solution:**

According to the formulae computed above, we have,

Area of a square = (side)

^{2. }Here

Side = 2 cm

Therefore, Area = 2

^{2 }cm^{2}= 4 cm

^{2 }…..IArea of rectangle = length x breadth

We have,

length = 3 cm

breadth = 2 cm

Therefore, Area = 3 × 2 cm

^{2}= 6 cm

^{2}…..IIAnd, area of triangle = 1/2 × Base × Height

= 1/2 × 4 × 2 cm

^{2}= 4 cm

^{2}…. IIITherefore, on comparing, we have,

Area of rectangle > Area of square = Area of triangle

### Similar Questions

**Question 1: Calculate which shape encloses more area;**

**Square with sides 10 m,**

**Rectangle with 11 m length and 10 m breadth,**

**Triangle with height 20 m and base 11 m**

**Solution: **

As we know that

I. Area of square = Side × Side

Area of square = Side

^{2}Given : Side of square is 10 m

Area of square = 10

^{2}Area of square = 10 × 10

Area of square = 100 m

^{2}II. Area of rectangle = Length × Breadth

Given : Length is 11 m and Breadth is 10 m

Area of rectangle = 11 × 10

Area of rectangle = 110 m

^{2}III. Area of triangle = 1/2 × Base × Height

Given : Base is 11 m and Height is 20 m

Area of triangle = 1/2 × 11 × 20

Area of triangle = 110 m

^{2}Therefore From I, II and III we get;

Area of square = 100 m

^{2}Area of rectangle = 110 m

^{2}Area of triangle = 110 m

^{2}Thus,

Area of Rectangle = Area of triangle > Area of square.

**Question 2: Calculate in these of the shape which shape will enclose more area?**

**Circle having radius 20 cm (Use π = 3.14)**

**Parallelogram having base of 40 cm and height of 30 cm**

**Trapezium having parallel side 15 cm and 20 cm and height 40 cm**

**Solution:**

I. Area of circle = πr

^{2}Given : Radius is 20 cm

Area of circle = 3.14 × 20 × 20 (Using π = 3.14)

Area of circle = 1256 cm

^{2}II. Area of parallelogram = Base × Height

Given : Base is 40 cm and Height is 30 cm

Area of parallelogram = 40 × 30

Area of parallelogram = 1200 cm

^{2}III. Area of trapezium = 1/2 × (Sum of parallel sides) × Height

Given : Height is 40 cm and Parallel side are 15 cm and 20 cm

Area of trapezium = 1/2 × (15 + 20) × 40

Area of trapezium = 700 cm

^{2}Therefore,

Area of circle (1256 cm

^{2}) > Area of parallelogram (1200 cm^{2}) > Area of trapezium (700 cm^{2}).

**Question 3. Find which figure has maximum perimeter?**

**Square of sides 50 m**

**Rectangle of length 65 m and breadth 30 m**

**Equilateral triangle of side 65 m**

**Solution:**

Here,

I. Perimeter of square = 4 × Side

Given : Side is 50 m

Perimeter of square = 4 × 50

Perimeter of square = 200 m

II. Perimeter of rectangle = 2 × (Length + Breadth)

Given : Length is 65 m and breadth is 30 m

Perimeter of rectangle = 2 × (65 + 30)

Perimeter of rectangle = 2 × 95

Perimeter of rectangle = 190 m

III. Perimeter of Equilateral triangle = Side + Side + Side

Given : Side is 65 m

Perimeter of Equilateral triangle = 65 + 65 + 65

Perimeter of Equilateral triangle = 195 m

Therefore,

Perimeter of square = 200 m > Perimeter of Equilateral triangle = 195 m > Perimeter of rectangle = 190 m.

**Question 4. Find how many small square of side 2 m and be formed from a large square of side 8 m?**

**Solution:**

As we know that,

Area of square = Side × Side

Area of large square = 8 × 8

Area of large square = 64 m

^{2}Now,

Area of small square = Side × Side

Area of small square = 2 × 2

Area of small square = 4 m

^{2}Further finding how many small squares can be formed from the large square

⇒ Area of large square/Area of small square

⇒ 64/4

⇒ 16 times

Therefore,

16 small square can be formed from a large square.

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