What’s difference between “array” and “&array” for “int array[5]” ?

If someone has defined an array such as “int array[5]”, what’s the meaning of “array” or “&array”? Are they both same or are they different? You might be tempted to think that they both would point to the very first element of the array i.e. they both will have same address. Let us find out!

To check this, the very first thing that comes to mind is the following program.

filter_none

edit
close

play_arrow

link
brightness_4
code

#include "stdio.h"
int main()
{
   int array[5];
  
   /* If %p is new to you, you can use %d as well */
   printf("array=%p : &array=%p\n", array, &array);
  
   return 0;
}

chevron_right






                        filter_none








So you got same address for both “array” and “&array”. Again, you are tempted to think that both are same. Well, they aren’t not! How come a variable and its & (i.e. address-of) be same. It doesn’t look logical but we saw that both “array” and “&array” are printing same address. May be it’s too soon to conclude. The crux of this post is that even though they both are resulting in same address but they are different types of addresses. And this is the difference between “array” and “&array”.


And just to show this difference, I would suggest to take a look at the following program.











                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















#include "stdio.h" 


int main() 


{ 


   int array[5]; 


  


   /* If %p is new to you, you can use %d as well */


   printf("array=%p : &array=%p\n", array, &array);  


  


   printf("array+1 = %p : &array + 1 = %p", array+1, &array+1); 


  


   return 0; 


} 



















                        chevron_right







                        filter_none








With pointer arithmetic, we know what happens when we add an integer to a pointer. So can you guess the output of the above program without running it? Shouldn’t “array+1” and “&array+1” point to same address. Well you might be surprised 🙂




Basically, “array” is a “pointer to the first element of array” but “&array” is a “pointer to whole array of 5 int”. Since “array” is pointer to int, addition of 1 resulted in an address with increment of 4 (assuming int size in your machine is 4 bytes). Since “&array” is pointer to array of 5 ints, addition of 1 resulted in an address with increment of 4 x 5 = 20 = 0x14. Now you see why these two seemingly similar pointers are different at core level. This logic can be extended to multidimensional arrays as well. Suppose double twoDarray[5][4] is a 2D array. Here, “twoDarray” is a pointer to array of 4 int but “&twoDarray” is pointer to array of 5 rows arrays of 4 int”. If this sounds cryptic, you can always have a small program to print these after adding 1. We hope that we could clarify that any array name itself is a pointer to the first element but & (i.e. address-of) for the array name is a pointer to the whole array itself.


Please do Like/Tweet/G+1 if you find the above useful. Also, please do leave us comment for further clarification or info. We would love to help and learn 🙂




Don’t stop now and take your learning to the next level. Learn all the important concepts of Data Structures and Algorithms with the help of the most trusted course: DSA Self Paced. Become industry ready at a student-friendly price.





    

        My Personal Notes
        arrow_drop_up
    

    

        
        

            
            
        

    


Recommended Posts: