This article aims at explaining and exploring the vulnerability in the input() function in Python 2.x. In Python 3, the raw_input() function was erased, and it’s functionality was transferred to a new built-in function known as input().

**Ways to input data in Python 2.x**

There are two common methods to receive input in Python 2.x:

- Using the
**input() function:**This function takes the value and type of the input you enter**as it is**without modifying any type. - Using the
**raw_input() function**: This function**explicitly converts**the input you give to type string,

Let us use the following program to determine the difference between the two:

`# Python 2.x program to show differences between` `# input() and rawinput()function ` ` ` `# 3 inputs using raw_input() function, ` `# after which data type of the value` `# entered is displayed` `s1 ` `=` `raw_input` `(` `"Enter input to test raw_input() function: "` `)` `print` `type` `(s1)` ` ` `s2 ` `=` `raw_input` `(` `"Enter input to test raw_input() function: "` `)` `print` `type` `(s2)` ` ` `s3 ` `=` `raw_input` `(` `"Enter input to test raw_input() function: "` `)` `print` `type` `(s3)` ` ` `# 3 inputs using input() function, ` `# after which data type of the value` `# entered is displayed` `s4 ` `=` `input` `(` `"Enter input to test input() function: "` `)` `print` `type` `(s4)` ` ` `s5 ` `=` `input` `(` `"Enter input to test input() function: "` `)` `print` `type` `(s5)` ` ` `s6 ` `=` `input` `(` `"Enter input to test input() function: "` `)` `print` `type` `(s6)` |

Input:

Hello 456 [1,2,3] 45 "goodbye" [1,2,3]

Output:

Enter input to test raw_input() function: <type 'str'> Enter input to test raw_input() function: <type 'str'> Enter input to test raw_input() function: <type 'str'> Enter input to test input() function: <type 'int'> Enter input totest input() function: <type 'str'> Enter input to test input() function: <type 'list'>

**Note:** While giving string input in the input() function, we have to enclose to value in double quotes. This is not required in raw_input()

**Vulnerability in input() method**

The vulnerability in input() method lies in the fact that the variable accessing the value of input can be accessed by anyone just by using the name of variable or method. Let’s explore these one by one:

**Variable name as input parameter:**The variable having the value of input variable is able to access the value of the input variable directly.`# Python 2.x program to show Vulnerabilities`

`# in input() function using a variable`

`import`

`random`

`secret_number`

`=`

`random.randint(`

`1`

`,`

`500`

`)`

`print`

`"Pick a number between 1 to 500"`

`while`

`True`

`:`

`res`

`=`

`input`

`(`

`"Guess the number: "`

`)`

`if`

`res`

`=`

`=`

`secret_number:`

`print`

`"You win"`

`break`

`else`

`:`

`print`

`"You lose"`

`continue`

Input:

15

Output:

Pick a number between 1 to 500 Guess the number: You lose Guess the number:

Input:

secret_number

Output:

Pick a number between 1 to 500 Guess the number: You win

As it can be seen, in second case the variable “secret_number” can be directly given as input and answer is always “You won”. It evaluates the variable as if a number was directly entered, by which means it returns a True Boolean always. Using raw_input, it would not be possible as it disallows to read the variable directly.

**Function name as parameter:**The vulnerability lies here as we can even provide the name of a function as input and access values that are otherwise not meant to be accessed.`# Python 2.x program to demonstrate input() function`

`# vulnerability by passing function name as parameter`

`secret_value`

`=`

`500`

`# function that returns the secret value`

`def`

`secretfunction():`

`return`

`secret_value`

`# using raw_input() to enter the number`

`input1`

`=`

`raw_input`

`(`

`"Raw_input(): Guess secret number: "`

`)`

`# input1 will be explicitly converted to a string`

`if`

`input1`

`=`

`=`

`secret_value:`

`print`

`"You guessed correct"`

`else`

`:`

`print`

`"wrong answer"`

`# using input() to enter the number`

`input2`

`=`

`input`

`(`

`"Input(): Guess the secret number: "`

`)`

`#input2 is evaluated as it is entered`

`if`

`input2`

`=`

`=`

`secret_value:`

`print`

`"You guessed correct"`

`else`

`:`

`print`

`"wrong answer"`

Input:

400 secretfunction()

Output:

Raw_input(): Guess secret number: wrong answer Input(): Guess the secret number: You guessed correct

In this set of input/output, we can see that when we use raw_input, we necessarily have to input the correct number. However while using the input() function, we can even provide the name of a function or variable, and the interpreter will evaluate that.

Here for example, the input for input() function has been given as the name of a function ‘secretfunction()’. The interpreter evaluates this function call and returns the secret number that we wish to find and hence our if condition evaluates to be true, even though we did not enter the secret numberInput:

secretfunction() secret_value

Output:

Raw_input(): Guess secret number: wrong answer Input(): Guess the secret number: You guessed correct

As explained in first point, in this example also we were able to simply enter the variable name ‘secret_number’ in the input for ‘input()’ function and we were able to gain access to the secret value.

However while trying to call secretfunction() in the input for the raw_input() function, it gives us false as the interpreter converts our argument to string, and doesn’t evaluate it as a function call.

**Preventing input vulnerabilities**

It is always better to use raw_input() in python 2.x and then explicitly convert the input to whatever type we require. For example, if we wish to take input of an integer, we can do the following

n = int(raw_input())

This prevents the malicious calling or evaluation of functions.

This article is contributed by **Deepak Srivatsav**. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

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