ValueRange checkValidIntValue() method in Java with Examples
The checkValidIntValue() method of ValueRange class is used to check that the value passed as parameter is valid and fits in an int. This method validates that the value passed as a parameter is within the valid range of values or not. For this method, it is important that the value return by method fits in it or not. The field passed as a parameter is only used to improve the error message. Syntax:
public int checkValidIntValue(long value, TemporalField field)
Parameters: This method accepts two parameters:
- value which is the value to check and
- scope which is the field being checked, may be null.
Return value: This method returns the value that was passed in. Below programs illustrate the ValueRange.checkValidIntValue() method: Program 1:
Java
import java.time.temporal.ValueRange;
public class GFG {
public static void main(String[] args)
{
ValueRange vRange = ValueRange.of( 1 , 10000 );
int value1 = vRange.checkValidIntValue( 500 , null );
System.out.println("Value passed :" + value1);
}
}
|
Output:
Value passed :500
Program 2:
Java
import java.time.temporal.ValueRange;
public class GFG {
public static void main(String[] args)
{
ValueRange vRange = ValueRange.of( 10000 , 99999 );
int value1 = vRange.checkValidIntValue( 44444 , null );
System.out.println("Value passed :" + value1);
}
}
|
Output:
Value passed :44444
References: https://docs.oracle.com/javase/10/docs/api/java/time/temporal/ValueRange.html#checkValidIntValue(long, java.time.temporal.TemporalField)
Last Updated :
17 Apr, 2023
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