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Using fork() to produce 1 parent and its 3 child processes
  • Last Updated : 13 May, 2018

Program to create four processes (1 parent and 3 children) where they terminates in a sequence as follows :
(a) Parent process terminates at last
(b) First child terminates before parent and after second child.
(c) Second child terminates after last and before first child.
(d) Third child terminates first.

Prerequisite : fork(),

    // CPP code to create three child
    // process of a parent
    #include <stdio.h>
    #include <stdlib.h>
    #include <unistd.h>
    // Driver code
    int main()
        int pid, pid1, pid2;
        // variable pid will store the
        // value returned from fork() system call
        pid = fork();
        // If fork() returns zero then it
        // means it is child process.
        if (pid == 0) {
            // First child needs to be printed
            // later hence this process is made
            // to sleep for 3 seconds.
            // This is first child process
            // getpid() gives the process
            // id and getppid() gives the
            // parent id of that process.
            printf("child[1] --> pid = %d and ppid = %d\n",
                   getpid(), getppid());
        else {
            pid1 = fork();
            if (pid1 == 0) {
                printf("child[2] --> pid = %d and ppid = %d\n",
                       getpid(), getppid());
            else {
                pid2 = fork();
                if (pid2 == 0) {
                    // This is third child which is
                    // needed to be printed first.
                    printf("child[3] --> pid = %d and ppid = %d\n",
                           getpid(), getppid());
                // If value returned from fork()
                // in not zero and >0 that means
                // this is parent process.
                else {
                    // This is asked to be printed at last
                    // hence made to sleep for 3 seconds.
                    printf("parent --> pid = %d\n", getpid());
        return 0;


    child[3]-->pid=50 and ppid=47
    child[2]-->pid=49 and ppid=47
    child[1]-->pid=48 and ppid=47

This code runs on Linux platform.

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