Open In App

URL toURI() method in Java with Examples

Improve
Improve
Like Article
Like
Save
Share
Report

The getURI() function of URL class converts the URL object to a URI object. Any URL which compiles with RFC 2396 can be converted to URI. URLs which are not in the specified format will generate an error if converted to URI format.

Function Signature

public URI toURI()

Syntax

url.toURI()

Parameter: This method do not accept any parameter.

Return type: This function returns a URI object which is converted from this URL object.

Exception: This function throws URISyntaxException if this URL is not formatted strictly according to RFC2396 and cannot be converted to a URI.

Below examples will illustrate the use of toURI() function:

Example 1:




// Java program to convert URL to URI
  
import java.net.*;
  
class GFG {
    public static void main(String args[])
    {
  
        // url and uri objects
        URL url = null;
        URI uri = null;
  
        try {
  
            // create a URL
            url = new URL("https://www.geeksforgeeks.org");
  
            // display the URL
            System.out.println("URL: " + url);
  
            // convert the URL to URI
            uri = url.toURI();
  
            // display the URI
            System.out.println("URI: " + uri);
        }
        // if any error occurs
        catch (Exception e) {
  
            // display the error
            System.out.println(e);
        }
    }
}


Output:

URL: https://www.geeksforgeeks.org
URI: https://www.geeksforgeeks.org

Example 2:




// Java program to convert URL to URI
  
import java.net.*;
  
class GFG {
    public static void main(String args[])
    {
  
        // url and uri objects
        URL url = null;
        URI uri = null;
  
        try {
  
            // create an invalid URL
            url = new URL("https://www.geeksfor>geeks.com");
  
            // display the URL
            System.out.println("URL: " + url);
  
            // convert the URL to URI
            uri = url.toURI();
  
            // display the URI
            System.out.println("URI: " + uri);
        }
        // if any error occurs
        catch (Exception e) {
  
            // display the error
            System.out.println(e);
        }
    }
}


Output:

URL: https:// www.geeksfor>geeks.com
java.net.URISyntaxException:
 Illegal character in authority at index 8:
 https:// www.geeksfor>geeks.com


Last Updated : 07 Nov, 2019
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads