Unset the last m bits

Given a non-negative number n. The problem is to unset the last m bits in the binary representation of n.
Constraint: 1 <= m <= num, where num is the number of bits in the binary representation of n.

Examples: 

Input : n = 10, m = 2
Output : 8
(10)10 = (1010)2
(8)10 = (1000)2
The last two bits in the binary 
representation of 10 have been unset.

Input : n = 150, m = 4
Output : 144

Approach: Following are the steps: 

1. Calculate num = (1 << (sizeof(int) * 8 – 1)) – 1. This will produce the highest positive integer num. All the bits in num will be set.
2. Toggle the last m bits in num. Refer this post.
3. Now, perform n = n & num. This will unset the last m bits in n.
4. Return n.

Note: The sizeof(int) has been used as input is of int data type. For large inputs you can use long int or long long int datatypes in place of int. 

C++

// C++ implementation to unset bits the last m bits
#include <bits/stdc++.h>
using namespace std;

// function to toggle the last m bits
unsigned int toggleLastMBits(unsigned int n,
                             unsigned int m)
{
    // calculating a number 'num' having 'm' bits
    // and all are set
    unsigned int num = (1 << m) - 1;

    // toggle the last m bits and return the number
    return (n ^ num);
}

// function to unset bits the last m bits
unsigned int unsetLastMBits(unsigned int n,
                            unsigned int m)
{
    // 'num' is the highest positive integer number
    // all the bits of 'num' are set
    unsigned int num = (1 << (sizeof(int) * 8 - 1)) - 1;

    // toggle the last 'm' bits in 'num'
    num = toggleLastMBits(num, m);

    // unset the last 'm' bits in 'n'
    // and return the number
    return (n & num);
}

// Driver program to test above
int main()
{
    unsigned int n = 150, m = 4;
    cout << unsetLastMBits(n, m);
    return 0;
}

Java

// Java implementation to unset
// bits the last m bits
class GFG
{

static int sizeofInt = 8;

// function to toggle the last m bits
static int toggleLastMBits(int n,
                            int m)
{
    // calculating a number 'num' having 'm' bits
    // and all are set
    int num = (1 << m) - 1;

    // toggle the last m bits and return the number
    return (n ^ num);
}

// function to unset bits the last m bits
static int unsetLastMBits(int n,
                            int m)
{
    // 'num' is the highest positive integer number
    // all the bits of 'num' are set
    int num = (1 << (sizeofInt * 8 - 1)) - 1;

    // toggle the last 'm' bits in 'num'
    num = toggleLastMBits(num, m);

    // unset the last 'm' bits in 'n'
    // and return the number
    return (n & num);
}

// Driver code
public static void main(String[] args)
{
    int n = 150, m = 4;
    System.out.println(unsetLastMBits(n, m));
}
}

/* This code is contributed by PrinciRaj1992 */

Python3

# Python3 implementation to unset
# bits the last m bits
import sys

# function to toggle the last m bits
def toggleLastMBits (n, m):

    # calculating a number 'num'
    # having 'm' bits and all are set
    num = (1 << m) - 1

    # toggle the last m bits
    # and return the number
    return (n ^ num)

# function to unset bits
# the last m bits
def unsetLastMBits(n, m):

    # 'num' is the highest positive integer
    # number all the bits of 'num' are set
    num = (1 << (sys.getsizeof(int) * 8 - 1)) - 1

    # toggle the last 'm' bits in 'num'
    num = toggleLastMBits(num, m)

    # unset the last 'm' bits in 'n'
    # and return the number
    return (n & num)

# Driven code
n = 150
m = 4
print (unsetLastMBits(n, m))

# This code is contributed by "rishabh_jain".

C#

// C# implementation to unset
// bits the last m bits
using System;

class GFG
{

static int sizeofInt = 8;

// function to toggle the last m bits
static int toggleLastMBits(int n,
                            int m)
{
    // calculating a number 'num' having 'm' bits
    // and all are set
    int num = (1 << m) - 1;

    // toggle the last m bits and return the number
    return (n ^ num);
}

// function to unset bits the last m bits
static int unsetLastMBits(int n,
                            int m)
{
    // 'num' is the highest positive integer number
    // all the bits of 'num' are set
    int num = (1 << (sizeofInt * 8 - 1)) - 1;

    // toggle the last 'm' bits in 'num'
    num = toggleLastMBits(num, m);

    // unset the last 'm' bits in 'n'
    // and return the number
    return (n & num);
}

// Driver code
public static void Main(String[] args)
{
    int n = 150, m = 4;
    Console.WriteLine(unsetLastMBits(n, m));
}
}

// This code is contributed by Rajput-Ji

PHP

<?php
// php implementation to unset
// bits the last m bits

// function to toggle
// the last m bits
function toggleLastMBits($n, $m)
{

    // calculating a number 'num'
    // having 'm' bits
    // and all are set
    $num = (1 << $m) - 1;

    // toggle the last m bits
    // and return the number
    return ($n ^ $num);
}

// function to unset bits
// the last m bits
function unsetLastMBits($n,$m)
{

    // 'num' is the highest positive
    // integer number all the bits
    // of 'num' are set

    //4 is Size of integer 32 bit
    $num = (1 << (4 * 8 - 1)) - 1;

    // toggle the last 'm' bits in 'num'
    $num = toggleLastMBits($num, $m);

    // unset the last 'm' bits in 'n'
    // and return the number
    return ($n & $num);
}

    // Drivercode
    $n = 150;
    $m = 4;
    echo unsetLastMBits($n, $m);

// This code is contributed by mits
?>

Javascript

<script>

// JavaScript implementation to unset
// bits the last m bits
let sizeofLet = 8;

// Function to toggle the last m bits
function toggleLastMBits(n, m)
{

    // Calculating a number 'num' having
    // 'm' bits and all are set
    let num = (1 << m) - 1;

    // Toggle the last m bits and
    // return the number
    return (n ^ num);
}

// Function to unset bits the last m bits
function unsetLastMBits(n, m)
{

    // 'num' is the highest positive
    // integer number all the bits of
    // 'num' are set
    let num = (1 << (sizeofLet * 8 - 1)) - 1;

    // Toggle the last 'm' bits in 'num'
    num = toggleLastMBits(num, m);

    // unset the last 'm' bits in 'n'
    // and return the number
    return (n & num);
}

// Driver Code
let  n = 150, m = 4;

document.write(unsetLastMBits(n, m));

// This code is contributed by sanjoy_62

</script>

Output:

144

Time Complexity: O(1)
Auxiliary Space: O(1)