The ‘=’ is an operator in C++ STL which copies (or moves) an unordered_set to another unordered_set and unordered_set::operator= is the corresponding operator function. There are three versions of this function.
- The first version takes reference of an unordered_set as an argument and copies it to an unordered_set.
- The second version performs a move assignment i.e it moves the content of an unordered_set to another unordered_set.
- The third version assigns contents of an initializer list to an unordered_set.
Syntax
uset.operator= ( unordered_set& us ) uset.operator= ( unordered_set&& us ) uset.operator= ( initializer list )
Parameters:
- The first version takes the reference of an unordered_set as argument.
- The second version takes the r-value reference of an unordered_set as argument.
- The third version takes an initializer list as argument.
Return value: All of them returns the value of this pointer(*this) . Below program illustrates the unordered_set::operator= in C++.
Program:
CPP
// C++ code to illustrate the method // unordered_set::operator=() #include <iostream> #include <unordered_set> using namespace std;
// merge function template < class T>
T merge(T a, T b) { T t(a);
t.insert(b.begin(), b.end());
return t;
} int main()
{ unordered_set< int > sample1, sample2, sample3;
// List initialization
sample1 = { 7, 8, 9 };
sample2 = { 9, 10, 11, 12 };
// Merge both lists
sample3 = merge(sample1, sample2);
// copy assignment
sample1 = sample3;
// Print the unordered_set list
for ( auto it = sample1.begin(); it != sample1.end(); ++it)
cout << *it << " " ;
cout << endl;
for ( auto it = sample2.begin(); it != sample2.end(); ++it)
cout << *it << " " ;
cout << endl;
for ( auto it = sample3.begin(); it != sample3.end(); ++it)
cout << *it << " " ;
cout << endl;
} |
Output:
10 11 12 7 8 9 12 11 10 9 10 11 12 7 8 9
Time complexity: O(n)
Auxiliary Space: O(n)