unordered_set get_allocator() in C++ STL with Examples

The get_allocator() method of unordered_set is the part of Standard Template Library(STL) of C++. This method gets the stored allocator object and returns it.

Syntax:

Allocator_type get_allocator() const;

where allocator_type is the type of the allocator used by the container.

Return Value: It returns the allocator object used to construct the container.

Exceptions: In this method, Exception is thrown if any element comparison object throws exception.

Below program illustrate the unordered_set::get_allocator() function

Program 1:

// CPP program to illustrate 
// unordered_set get_allocator() 
  
#include <iostream> 
#include <unordered_set> 
  
using namespace std; 
int main() 
{ 
  
    //'c' is object of 'unordered_set' 
    unordered_set<int> c; 
  
    //'allocator_type' is inherit in 'unordered_set' 
    //'a' is object of 'allocator_type' 
    //'get_allocator()' is member of 'unordered_set' 
    unordered_set<int>::allocator_type a = c.get_allocator(); 
  
    // Comparing the Allocator with Pair<int, int> 
    cout << "Is allocator Pair<int, int> : "
         << boolalpha 
         << (a == allocator<pair<int, int> >()); 
  
    return 0; 
} 

Output:

Is allocator Pair : true

Complexity :
It takes constant(O(1)) time of complexity to perform an operation.

Program 2 :

// CPP program to illustrate 
// unordered_set get_allocator() 
  
#include <iostream> 
#include <unordered_map> 
  
using namespace std; 
  
int main(void) 
{ 
    unordered_map<char, int> um; 
    pair<const char, int>* a; 
  
    a = um.get_allocator().allocate(8); 
  
    cout << "Allocated size = " << sizeof(*a) * 8 << endl; 
  
    return 0; 
} 

Output:

Allocated size = 64

My Personal Notes

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