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UGC-NET | UGC NET CS 2018 July – II | Question 52
  • Last Updated : 07 Sep, 2018

In a paged memory, the page hit ratio is 0.40. The time required to access a page in secondary memory is equal to 120 ns. The time required to access a page in primary memory is 15 ns. The average time required to access a page is ________.
(A) 105
(B) 68
(C) 75
(D) 78


Answer: (D)

Explanation: Average access time = hit ratio * primary memory access time + (1 – hit ratio) * secondary memory access time
Average access time = 0.4 * 15 + 0.6 * 120
Average access time = 6 + 72
Average access time = 78.
So, option (D) is correct.

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