UGC-NET | UGC NET CS 2018 July – II | Question 42

The period of a signal is 100 ms. Its frequency is _________.
(A) 1003Hertz
(B) 10-2KHz
(C) 10-3KHz
(D) 105 Hertz


Answer: (B)

Explanation: We know that:
frequency(f) = 1 / Timeperiod(T)
Given timeperiod(T) = 100 ms
f = 1 / 100ms
f = 1000 / 100000 ms
We know that 1000 ms = 1 sec and we can write 1000 as 1 k
i.e. f = 1k / 100s
f = 10-2 kHz (1 / s = Hz)
So, option (B) is correct.


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