• Courses
  • Tutorials
  • Jobs
  • Practice
  • Contests

UGC-NET | UGC-NET CS 2017 Nov - III | Question 32

You are given a sequence of n elements to sort. The input sequence consists of n/k subsequences,each containing k elements. The elements in a given subsequence are all smaller than the elements in the succeeding subsequence and larger than the elements in the preceding subsequence. Thus, all that is needed to sort the whole sequence of length n is to sort the k elements in each of the n/k subsequences. The lower bound on the number of comparisons needed to solve this variant of the sorting problem is

(A)

Ω (n)

(B)

Ω (n/k)

(C)

Ω (nlogk )

(D)

Ω (n/klogn/k)

Answer

Please comment below if you find anything wrong in the above post
Feeling lost in the world of random DSA topics, wasting time without progress? It's time for a change! Join our DSA course, where we'll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 geeks!

Last Updated :
Share your thoughts in the comments