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UGC-NET | UGC NET CS 2017 Jan – III | Question 49
  • Last Updated : 04 Apr, 2018

A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and physical address are respectively:
(A) 14 and 15
(B) 14 and 29
(C) 15 and 14
(D) 16 and 32


Answer: (C)

Explanation:

we know that Number of pages = virtual memory space / page size.
and Number of frames = physical memory space / frame size.
and page size is equal to frame size. 
According to question and given data:
      virtual memory space = Number of pages * page size
i.e.  virtual memory space = 64 * 512 B
      virtual memory space = 26 * 29B
                  i.e.     = 215B.
So, 15 bits are required for virtual memory space.
 physical memory space =  Number of frames * frame size.
 physical memory space = 32 * 512 B
 physical memory space = 25 * 29B
                i.e.   = 214B.
So, 14 bits are required for virtual memory space.

So, option (C) is correct.

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