UGC-NET | UGC NET CS 2017 Jan – II | Question 10

The hexadecimal equivalent of the octal number 2357 is :
(A) 2EE
(B) 2FF
(C) 4EF
(D) 4FE


Answer: (C)

Explanation: First we will convert 2357 into binary: 010 011 101 111 now we will group this binary number into group of 4 → 0100 1110 1111 now place the hexadecimal equivalent ie 1111 – F, 1110 – E, 0100 – 4. Hexadecimal no is 4EF.
So, option (E) is correct.

Quiz of this Question



My Personal Notes arrow_drop_up


Article Tags :

Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.