UGC-NET | UGC-NET CS 2017 Dec 2 | Question 5 Last Updated : 12 Mar, 2018 Improve Improve Like Article Like Save Share Report The Octal equivalent of the binary number 1011101011 is : (A) 7353 (B) 1353 (C) 5651 (D) 5657 Answer: (B) Explanation: Quiz of this QuestionPlease comment below if you find anything wrong in the above post Like Article Suggest improvement Previous UGC-NET | UGC NET CS 2015 Dec – III | Question 25 Next UGC-NET | UGC-NET CS 2017 Dec 2 | Question 1 Share your thoughts in the comments Add Your Comment Please Login to comment...