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UGC-NET | UGC NET CS 2016 July – III | Question 25

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If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ______.
(A) 64 Kbps
(B) 32 Mbps
(C) 32 Kbps
(D) 64 MbpS


Answer: (C)

Explanation: Transmission rate = frame rate * no of bits in a slot.
Frame rate = 4000 frames per second
# of bits in a slot = 8 bit
TDM = 4000 * 8 bps = 32 Kbps.
So, option (C) is correct.


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Last Updated : 24 Apr, 2018
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