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UGC-NET | UGC NET CS 2016 Aug – III | Question 27

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In CRC checksum method, assume that given frame for transmission is 1101011011 and the generator polynomial is G(x) = x4 + x + 1. After implementing CRC encoder, the encoded word sent from sender side is _____. (A) 11010110111110 (B) 11101101011011 (C) 110101111100111 (D) 110101111001111

Answer: (A)

Explanation: Given frame for transmission is 1101011011 and generator polynomial is G(x) = x4 + x + 1 i.e. 10011. We have to append 4 0’s (1 0’s less then divisor according to CRC): 27 (1) We have to append 1110 to the frame. Now our frame for transmission is 11010110111110. So, option (A) is correct.

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Last Updated : 17 Apr, 2018
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