Suppose transmission rate of a channel is 32 kbps. If there are ‘8’ routes from source to destination and each packet p contains 8000 bits. Total end to end delay in sending packet P is _____.
(A) 2 sec
(B) 3 sec
(C) 4 sec
(D) 1 sec


Answer: (A)

Explanation: It is given that transmission rate of a channel is 32 kbps and ‘8’ routes from source to destination and each packet p contains 8000 bits.
Total delay = routes * packets / transmission rate.
i.e. 8 * 8000 b / 32 kbps
= 8 * 8000 b / 32000 bps
= 2 s
So, option (A) is correct.

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