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UGC-NET | UGC NET CS 2015 Jun – III | Question 29

  • Last Updated : 20 Jun, 2018

Suppose a digitized voice channel is made by digitizing 8 kHz bandwidth analog voice signal. It is required to sample the signal at twice the highest frequency (two samples per hertz). What is the bit rate required, if it is assumed that each sample requires 8 bits?
(A) 32 kbps
(B) 64 kbps
(C) 128 kbps
(D) 256 kbps


Answer: (C)

Explanation: According to question:
It is required to sample the signal at twice the highest frequency (two samples per hertz).
So, bit rate = current bandwidth * 2 * sample size.
bit rate = 8 KHz * 2 * 8 bit.
bit rate = 8 K / sec * 2 * 8 bit.
bit rate = 128 kb / sec.
bit rate = 128 Kbps.
So, option (C) is correct.


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