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UGC-NET | UGC NET CS 2015 Dec – II | Question 35

  • Last Updated : 02 May, 2018

The hash function used in double hashing is of the form:
(A) h (k, i) = (h1(k) + h2(k) + i) mod m
(B) h (k, i) = (h1(k) + h2(k) – i) mod m
(C) h (k, i) = (h1(k) + i * h2(k)) mod m
(D) h (k, i) = (h1(k) – i * h2(k) ) mod m


Answer: (C)

Explanation: h(k, i) = (h1(k) + i * h2(k)) mod m is used in double hashing is of the form. Rest other option does not used in double hashing.
So, option (C) is correct.

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