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UGC-NET | UGC NET CS 2015 Dec - II | Question 35
The hash function used in double hashing is of the form:
(A)
h (k, i) = (h1(k) + h2(k) + i) mod m
(B)
h (k, i) = (h1(k) + h2(k) - i) mod m
(C)
h (k, i) = (h1(k) + i * h2(k)) mod m
(D)
h (k, i) = (h1(k) - i * h2(k) ) mod m
Answer
Please comment below if you find anything wrong in the above post
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