Skip to content
Related Articles

Related Articles

Improve Article
UGC-NET | UGC NET CS 2015 Dec – II | Question 23
  • Last Updated : 01 May, 2018

Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is __________.

(A) 400 bps
(B) 800 bps
(C) 1600 bps
(D) 3200 bps


Answer: (D)

Explanation: Number of channels = 4
1 byte is multiplexed with each channel i.e. each frame carries 1 byte and we have 4 channel, so the size of each frame is 1 * 4 byte = 4 bytes 32 bits.
Channel sends 100 frames per seconds. So, the bit rate will be 100 * 4 byte i.e. 3200 bits / seconds.
So, option (D) is correct.

Quiz of this Question

My Personal Notes arrow_drop_up
Recommended Articles
Page :