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UGC-NET | UGC NET CS 2014 Dec – II | Question 5

  • Last Updated : 25 Jun, 2018

If we define the functions f, g and h that map R into R by :
f(x) = x4 , g(x) = √(x2 + 1), h(x) = x2 + 72, then the value of the composite functions ho(gof) and (hog)of are given as
(A) x8 – 71 and x8 – 71
(B) x8– 73 and x8 – 73
(C) x8 + 71 and x8 + 71
(D) x8 + 73 and x8 + 73


Answer: (D)

Explanation: f(x) = x4, g(x) = √(x2 + 1) and h(x) = x2 + 72
Now ho(gof) = ho√(x8 + 1)
= x8 + 72 + 1
= x8 + 73.
We have to find (hog)of:
(hog)of = (x2 + 1) + 72
= x2 + 73
= x8 + 73.
So, option (D) is correct.


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