The following Context-Free Grammar (CFG):
S → aB | bA
A → a | aS | bAA
B → b | bS | aBB
will generate
(1) odd numbers of a’s and odd numbers of b’s
(2) even numbers of a’s and even numbers of b’s
(3) equal numbers of a’s and b’s
(4) different numbers of a’s and b’s
(A) (1)
(B) (2) an (3)
(C) (1), (2) and (3)
(D) All are correct.


Answer: (D)

Explanation: The following Context-Free Grammar (CFG):
S → aB | bA
A → a | aS | bAA
B → b | bS | aBB
will generate

Option (D) is correct.

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