Open In App

UGC-NET | UGC NET CS 2014 Dec – II | Question 35

Like Article
Like
Save
Share
Report

The following Context-Free Grammar (CFG): S → aB | bA A → a | aS | bAA B → b | bS | aBB will generate (1) odd numbers of a’s and odd numbers of b’s (2) even numbers of a’s and even numbers of b’s (3) equal numbers of a’s and b’s (4) different numbers of a’s and b’s

(A)

(1)

(B)

(2) an (3)

(C)

(1), (2) and (3)

(D)

All are correct.


Answer: (C)

Explanation:

Explanation: The following Context-Free Grammar (CFG): S → aB | bA A → a | aS | bAA B → b | bS | aBB will generate

  • odd numbers of a’s and odd numbers of b’s i.e. ab or ba.
  • even numbers of a’s and even numbers of b’s i.e. aabb or bbaa
  • equal numbers of a’s and b’s i.e.ab, ba bbaa or aabb
  • The grammar cannot produce variable numbers of a’s and b’s. i.e. abb or baa

Option (C) is correct.

Quiz of this Question


Quiz of this Question
Please comment below if you find anything wrong in the above post


Last Updated : 25 Jun, 2018
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads