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UGC-NET | UGC NET CS 2014 Dec – II | Question 24

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Consider a two dimensional array A[20][10]. Assume 4 words per memory cell, the base address of array A is 100, elements are stored in row-major order and first element is A[0][0]. What is the address of A[11][5] ?
(A) 560
(B) 460
(C) 570
(D) 575

Answer: (A)

Explanation: Element A[11][0] is stored at “Base Address + 11 * 10 * 4” which is “Base Address + 440” = 540. So A[11][5] is stored at 540 + 5*4 = 560.

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Last Updated : 07 Jun, 2019
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