UGC-NET | UGC NET CS 2014 Dec – II | Question 24
Consider a two dimensional array A. Assume 4 words per memory cell, the base address of array A is 100, elements are stored in row-major order and first element is A. What is the address of A ?
Explanation: Element A is stored at “Base Address + 11 * 10 * 4” which is “Base Address + 440” = 540. So A is stored at 540 + 5*4 = 560.
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