# UGC NET CS 2017 Jan – II

 Question 1
Consider a sequence F00 defined as : F00(0) = 1, F00(1) = 1 F00(n) = 10 ∗ F00(n – 1) + 100 F00(n – 2) for n ≥ 2 Then what shall be the set of values of the sequence F00 ?
 A (1, 110, 1200) B (1, 110, 600, 1200) C (1, 2, 55, 110, 600, 1200) D (1, 55, 110, 600, 1200)
Dynamic Programming    UGC NET CS 2017 Jan - II
Discuss it

Question 1 Explanation:
``` F00(0) = 1, F00(1) = 1
F00(n) = 10 ∗ F00(n – 1) + 100
F00(2) = 10 * F00(1) + 100
= 10 * 1 + 100
= 10 + 100
= 110
Similarly:
F00(3) = 10 * F00(2) + 100
= 10 * 110 + 100
= 1100 + 100
= 1200
The sequence will be (1, 110, 1200).```
So, (A) will be the answer.
 Question 2
Match the following : A (1) B (2) C (3) D (4)
UGC NET CS 2017 Jan - II
Discuss it

Question 2 Explanation:
1. Absurd means Clearly impossible being contrary to some evident truth.
2. Ambiguous Capable of more than one interpretation or meaning.
3. An assertion that is accepted and used without a proof.
4. Conjecture An opinion preferably based on some experience or wisdom
So, option (A) is correct.
 Question 3
The functions mapping R into R are defined as : f(x) = x3 – 4x, g(x) = 1/(x2 + 1) and h(x) = x4. Then find the value of the following composite functions : hog(x) and hogof(x)
 A (x2 + 1)4 and [(x3 – 4x)2 + 1]4 B (x2 + 1)4 and [(x3 – 4x)2 + 1]-4 C (x2 + 1)-4 and [(x3 – 4x)2 + 1]4 D (x2 + 1)-4 and [(x3 – 4x)2 + 1]-4
Numerical Methods and Calculus    UGC NET CS 2017 Jan - II
Discuss it

Question 3 Explanation:
``` f(x) = x3 – 4x, g(x) = 1/(x2 + 1) and h(x) = x4
hog(x) = [g(x)]4
=  [1/(x2 + 1)]4
=  [(x2 + 1)-1]4
=  [(x2 + 1)]-4
Similarly:
hogof(x) = [gof(x)]4
= [(f(x)2 + 1)]-4
=  [((x3 – 4x)2 + 1)]-4
```
So, option (D) is correct.
 Question 4
How many multiples of 6 are there between the following pairs of numbers ? 0 and 100 and –6 and 34
 A 16 and 6 B 17 and 6 C 17 and 7 D 16 and 7
General Aptitude    UGC NET CS 2017 Jan - II
Discuss it

Question 4 Explanation:
Between 0 and 100 multiple of 6 are: o,6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96 ie. 17 multiple. Between -6 and 34 multiple of 6 are: -6, 0, 6, 12, 18, 24, 30. ie. 7 multiple. So,option (C) is correct.
 Question 5
Consider a Hamiltonian Graph G with no loops or parallel edges and with |V(G)| = n ≥ 3. Then which of the following is true ?
 A deg(v) ≥n/2 for each vertex v. B |E(G)| ≥1/2(n – 1) (n – 2) + 2 C deg (v) + deg(w) ≥ n whenever v and w are not connected by an edge D All of the above
Graph Theory    UGC NET CS 2017 Jan - II
Discuss it

 Question 6
In propositional logic if (P → Q) ∧ (R → S) and (P ∨ R) are two premises such that (P → Q) ∧ (R → S) P ∨ R Y Y is the premise :
 A P ∨ R B P ∨ S C Q ∨ R D Q ∨ S
Propositional and First Order Logic.    UGC NET CS 2017 Jan - II
Discuss it

 Question 7
ECL is the fastest of all logic families. High speed in ECL is possible because transistors are used in difference amplifier configuration, in which they are never driven into ____.
 A Race condition B Saturation C Delay D High impedance
Propositional and First Order Logic.    UGC NET CS 2017 Jan - II
Discuss it

 Question 8
Convert the octal number 0.4051 into its equivalent decimal number.
 A 0.51001 B 0.2096 C 0.52 D 0.4192
Digital Logic & Number representation    Number Representation    UGC NET CS 2017 Jan - II
Discuss it

Question 8 Explanation:
Convert 0.4051 into decimal in traditional way:
```i.e.  4 * 8-1 + 0 * 8-2 + 5 * 8-3 + 1 * 8-4
= 0.5100098```
So, option (A) is correct.
 Question 9
The hexadecimal equivalent of the octal number 2357 is :
 A 2EE B 2FF C 4EF D 4FE
Digital Logic & Number representation    Number Representation    UGC NET CS 2017 Jan - II
Discuss it

Question 9 Explanation:
First we will convert 2357 into binary: 010 011 101 111 now we will group this binary number into group of 4 → 0100 1110 1111 now place the hexadecimal equivalent ie 1111 - F, 1110 - E, 0100 - 4. Hexadecimal no is 4EF. So, option (E) is correct.
 Question 10
Which of the following cannot be passed to a function in C++ ?
 A Constant B Structure C Array D Header file
Class and Object    UGC NET CS 2017 Jan - II
Discuss it

Question 10 Explanation:
Header file can not be passed to a function in C++. While array, constant and structure can be passed into a function. So, option (D) is correct.
There are 49 questions to complete.

My Personal Notes arrow_drop_up