Traverse a given Matrix using Recursion
Given a matrix arr of size N x M, the task is to traverse this matrix using recursion.
Examples:
Input: arr[][] = {{1, 2, 3},
{4, 5, 6},
{7, 8, 9}}
Output: 1, 2, 3, 4, 5, 6, 7, 8, 9
Input: M[][] = {{11, 12, 13},
{14, 15, 16},
{17, 18, 19}}
Output: 11, 12, 13, 14, 15, 16, 17, 18, 19
Approach: Below are the steps to traverse the Matrix recursively:
- Base Case: If the current row or column exceeds the size N or M, respectively, the recursion is stopped.
- If the current column exceeds the total number of columns M, then the next row is started.
if (current_col >= M) This row ends. Start for next row - If the current row exceeds the total number of rows N, then the complete traversal is stopped.
if (current_row >= N) Matrix has been traversed completely
- If the current column exceeds the total number of columns M, then the next row is started.
- Recursive Case: In each recursive call,
- The current element of the Matrix is printed.
- Two recursive calls are made:
- One to traverse the next row, and
- Another to traverse the next column.
After we print all the elements of the row and when we move on to the next column, this again calls the row in recursion, thereby printing all the elements of the matrix.
Below is the implementation of the above approach:
C++
// C++ program to traverse the matrix recursively #include <iostream> using namespace std; #define N 2 #define M 3 // Function to traverse the matrix recursively int traverseMatrix(int arr[N][M], int current_row, int current_col) { // If the entire column is traversed if (current_col >= M) return 0; // If the entire row is traversed if (current_row >= N) return 1; // Print the value of the current // cell of the matrix cout << arr[current_row][current_col] << ", "; // Recursive call to traverse the matrix // in the Horizontal direction if (traverseMatrix(arr, current_row, current_col + 1) == 1) return 1; // Recursive call for changing the // Row of the matrix return traverseMatrix(arr, current_row + 1, 0); } // Driver code int main() { int arr[N][M] = { { 1, 2, 3 }, { 4, 5, 6 } }; traverseMatrix(arr, 0, 0); return 0; } |
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Java
// Java program to traverse the matrix recursively class GFG { final static int N = 2; final static int M = 3; // Function to traverse the matrix recursively static int traverseMatrix(int arr[][], int current_row, int current_col) { // If the entire column is traversed if (current_col >= M) return 0; // If the entire row is traversed if (current_row >= N) return 1; // Print the value of the current // cell of the matrix System.out.print(arr[current_row][current_col] + ", "); // Recursive call to traverse the matrix // in the Horizontal direction if (traverseMatrix(arr, current_row, current_col + 1) == 1) return 1; // Recursive call for changing the // Row of the matrix return traverseMatrix(arr, current_row + 1, 0); } // Driver code public static void main (String[] args) { int arr[][] = { { 1, 2, 3 }, { 4, 5, 6 } }; traverseMatrix(arr, 0, 0); } } // This code is contributed by AnkitRai01 |
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C#
// C# program to traverse the matrix recursively using System; public class GFG { static int N = 2; static int M = 3; // Function to traverse the matrix recursively static int traverseMatrix(int [,]arr, int current_row, int current_col) { // If the entire column is traversed if (current_col >= M) return 0; // If the entire row is traversed if (current_row >= N) return 1; // Print the value of the current // cell of the matrix Console.Write(arr[current_row,current_col] + ", "); // Recursive call to traverse the matrix // in the Horizontal direction if (traverseMatrix(arr, current_row, current_col + 1) == 1) return 1; // Recursive call for changing the // Row of the matrix return traverseMatrix(arr, current_row + 1, 0); } // Driver code public static void Main (string[] args) { int [,]arr = { { 1, 2, 3 }, { 4, 5, 6 } }; traverseMatrix(arr, 0, 0); } } // This code is contributed by AnkitRai01 |
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Python3
# Python3 program to traverse the matrix recursively N = 2 M = 3 # Function to traverse the matrix recursively def traverseMatrix(arr, current_row, current_col) : # If the entire column is traversed if (current_col >= M) : return 0; # If the entire row is traversed if (current_row >= N) : return 1; # Print the value of the current # cell of the matrix print(arr[current_row][current_col],end= ", "); # Recursive call to traverse the matrix # in the Horizontal direction if (traverseMatrix(arr, current_row, current_col + 1 ) == 1) : return 1; # Recursive call for changing the # Row of the matrix return traverseMatrix(arr, current_row + 1, 0); # Driver code if __name__ == "__main__" : arr = [ [ 1, 2, 3 ], [ 4, 5, 6 ] ]; traverseMatrix(arr, 0, 0); # This code is contributed by AnkitRai01 |
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Output:
1, 2, 3, 4, 5, 6,
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Improved By : AnkitRai01
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