time.Time.UnmarshalBinary() Function in Golang with Examples
Last Updated :
10 May, 2020
In Go language, time packages supply functionality for determining as well as viewing time. The UnmarshalBinary() function in Go language is used to implement the encoding.BinaryUnmarshaler interface. Moreover, this function is defined under the time package. Here, you need to import the “time” package in order to use these functions.
Syntax:
func (t *Time) UnmarshalBinary(data []byte) error
Here, “t” is the pointer to the stated time, and “data” is the byte slice that decodes the form that was generated by MarshalBinary() method.
Return value: It decodes the form that was returned by MarshalBinary() method and returns an error occurred but if there is no error then “nil” is returned.
Example 1:
package main
import "fmt"
import "time"
func main() {
t := time .Date(2003, 4, 6, 12, 34, 33, 0, time .UTC)
encoding, _ := t.MarshalBinary()
var tm time .Time
decode := tm .UnmarshalBinary(encoding)
fmt.Printf( "Error: %v\n" , decode)
}
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Output:
Error: <nil>
Example 2:
package main
import "fmt"
import "time"
func main() {
t := time .Date(2020, 56, 76, 43, 99, 101, 3444, time .UTC)
encoding, _ := t.MarshalBinary()
var tm time .Time
decode := tm .UnmarshalBinary(encoding)
fmt.Printf( "Error: %v\n" , decode)
}
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Output:
Error: <nil>
Here, the “t” stated in the above code has values that are outside usual range but they are normalized while conversion.
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