# Time taken per hour for stoppage of Car

A car travels with an average speed of S km/h without any stoppage and with stoppage the speed of car reduces to an average of S1 km/h. The task is to find the time wasted per hour for the stoppage.

Examples:

Input: S = 50, S1 = 30
Output: 24 min

Input: S = 30, S1 = 10
Output: 40 min

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: Take the first example,

Speed of car without any stoppage = 50 kmph i.e. 50 km in 60 min.
Speed of car with stoppage = 30 kmph i.e. 30 km in 60 min.

Now, if there will be no stoppage then 30 km can be covered in 36 min.
50 km –> 60 min
30 km –> (60 / 50) * 30 = 36 min
but it takes 60 min.
So, time for stoppage per hour is 60 min – 36 min = 24 min.

This can be calculated using the below formula: Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach ` `#include ` `using` `namespace` `std; ` ` `  `// Function to return the time taken ` `// per hour for stoppage ` `int` `numberOfMinutes(``int` `S, ``int` `S1) ` `{ ` ` `  `    ``int` `Min = 0; ` ` `  `    ``Min = ((S - S1) / ``floor``(S)) * 60; ` ` `  `    ``return` `Min; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `S = 30, S1 = 10; ` ` `  `    ``cout << numberOfMinutes(S, S1) << ``" min"``; ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java implementation of the approach ` `import` `java.util.*; ` ` `  `class` `GFG  ` `{ ` ` `  `// Function to return the time taken ` `// per hour for stoppage ` `static` `int` `numberOfMinutes(``int` `S, ``int` `S1) ` `{ ` `    ``int` `Min = ``0``; ` ` `  `    ``Min = (``int``) (((S - S1) / Math.floor(S)) * ``60``); ` ` `  `    ``return` `Min; ` `} ` ` `  `// Driver code ` `public` `static` `void` `main(String[] args)  ` `{ ` `    ``int` `S = ``30``, S1 = ``10``; ` ` `  `    ``System.out.println(numberOfMinutes(S, S1) + ``" min"``); ` `} ` `} ` ` `  `// This code is contributed by Princi Singh `

## Python3

 `# Python3 implementation of the approach ` `import` `math  ` ` `  `# Function to return the time taken ` `# per hour for stoppage ` `def` `numberOfMinutes(S, S1): ` ` `  `    ``Min` `=` `0``; ` ` `  `    ``Min` `=` `((S ``-` `S1) ``/` `math.floor(S)) ``*` `60``; ` ` `  `    ``return` `int``(``Min``); ` ` `  `# Driver code ` `if` `__name__ ``=``=` `'__main__'``: ` `    ``S, S1 ``=` `30``, ``10``; ` ` `  `    ``print``(numberOfMinutes(S, S1), ``"min"``); ` ` `  `# This code is contributed by Rajput-Ji `

## C#

 `// C# implementation of the approach ` `using` `System; ` ` `  `class` `GFG  ` `{ ` ` `  `// Function to return the time taken ` `// per hour for stoppage ` `static` `int` `numberOfMinutes(``int` `S, ``int` `S1) ` `{ ` `    ``int` `Min = 0; ` ` `  `    ``Min = (``int``) (((S - S1) /  ` `                   ``Math.Floor((``double``)S)) * 60); ` ` `  `    ``return` `Min; ` `} ` ` `  `// Driver code ` `public` `static` `void` `Main()  ` `{ ` `    ``int` `S = 30, S1 = 10; ` ` `  `    ``Console.WriteLine(numberOfMinutes(S, S1) +  ` `                                      ``" min"``); ` `} ` `} ` ` `  `// This code is contributed  ` `// by Akanksha Rai  `

Output:

```40 min
```

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