time.Seconds() Function in Golang With Examples

In Go language, time packages supplies functionality for determining as well as viewing time. The Seconds() function in Go language is used to find the duration of time in the form of a floating-point number of seconds. Moreover, this function is defined under the time package. Here, you need to import the “time” package in order to use these functions.

Syntax:

```func (d Duration) Seconds() float64
```

Here, d is the duration of time.

Return value: It returns the duration value as float64.

Example 1:

 `// Golang program to illustrate the usage of ` `// Seconds() function ` ` `  `// Including main package ` `package main ` ` `  `// Importing fmt and time ` `import ( ` `    ``"fmt"` `    ``"time"` `) ` ` `  `// Calling main ` `func main() { ` ` `  `    ``// Defining duration  ` `    ``// of Seconds method ` `    ``sec, _ := ``time``.ParseDuration(``"7m"``) ` ` `  `    ``// Prints duration as a ` `    ``// floating point number ` `    ``fmt.Printf(``"Only %.1f seconds of "``+ ` `      ``"task is remaining."``, sec.Seconds()) ` `} `

Output:

```Only 420.0 seconds of task is remaining.
```

Example 2:

 `// Golang program to illustrate the usage of ` `// Seconds() function ` ` `  `// Including main package ` `package main ` ` `  `// Importing fmt and time ` `import ( ` `    ``"fmt"` `    ``"time"` `) ` ` `  `// Calling main ` `func main() { ` ` `  `    ``// Defining duration  ` `    ``// of Seconds method ` `    ``sec, _ := ``time``.ParseDuration(``"3h8m756s6576.587ns"``) ` ` `  `    ``// Prints duration as a ` `    ``// floating point number ` `    ``fmt.Printf(``"Only %.1f seconds of "``+ ` `     ``"task is remaining."``, sec.Seconds()) ` `} `

Output:

```Only 12036.0 seconds of task is remaining.
```

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