# Time difference between expected time and given time

• Difficulty Level : Easy
• Last Updated : 31 Mar, 2021

Given the initial clock time h1:m1 and the present clock time h2:m2, denoting hour and minutes in 24-hours clock format. The present clock time h2:m2 may or may not be correct. Also given a variable K which denotes the number of hours passed. The task is to calculate the delay in seconds i.e. time difference between expected time and given time.
Examples :

Input: h1 = 10, m1 = 12, h2 = 10, m2 = 17, k = 2
Output: 115 minutes
The clock initially displays 10:12. After 2 hours it must show 12:12. But at this point, the clock displays 10:17. Hence, the clock must be lagging by 115 minutes. so the answer is 115.
Input: h1 = 12, m1 = 00, h2 = 12, m2 = 58, k = 1
Output: 2 minutes
The clock initially displays 12:00. After 1 hour it must show 13:00. But at this point, the clock displays 12:58. Hence, the clock must be lagging by 2 minutes. so the answer is 2.

Approach

1. Convert given time in h:m format to number of minutes. It is simply 60*h+m.
2. Calculate both the computed time(adding K hours to the initial time).
3. Find the difference in minutes which will be the answer.

Below is the implementation of the above approach.

## C++

 `// C++ program to calculate clock delay``#include ` `// Function definition with logic``int` `lagDuration(``int` `h1, ``int` `m1, ``int` `h2, ``int` `m2, ``int` `k)``{``    ``int` `lag, t1, t2;` `    ``// Conversion to minutes``    ``t1 = (h1 + k) * 60 + m1;` `    ``// Conversion to minutes``    ``t2 = h2 * 60 + m2;` `    ``// Calculating difference``    ``lag = t1 - t2;``    ``return` `lag;``}` `// Driver Code``int` `main()``{``    ``int` `h1 = 12, m1 = 0;``    ``int` `h2 = 12, m2 = 58;``    ``int` `k = 1;` `    ``int` `lag = lagDuration(h1, m1, h2, m2, k);``    ``printf``(``"Lag = %d minutes"``, lag);` `    ``return` `0;``}`

## Java

 `// Java program to``// calculate clock delay``class` `GFG``{` `// Function definition``// with logic``static` `int` `lagDuration(``int` `h1, ``int` `m1,``                       ``int` `h2, ``int` `m2,``                       ``int` `k)``{``    ``int` `lag, t1, t2;` `    ``// Conversion to minutes``    ``t1 = (h1 + k) * ``60` `+ m1;` `    ``// Conversion to minutes``    ``t2 = h2 * ``60` `+ m2;` `    ``// Calculating difference``    ``lag = t1 - t2;``    ``return` `lag;``}` `// Driver Code``public` `static` `void` `main(String args[])``{``    ``int` `h1 = ``12``, m1 = ``0``;``    ``int` `h2 = ``12``, m2 = ``58``;``    ``int` `k = ``1``;` `    ``int` `lag = lagDuration(h1, m1, h2, m2, k);``    ``System.out.println(``"Lag = "` `+ lag +``                       ``" minutes"``);``}``}` `// This code is contributed``// by Kirti_Mangal`

## Python3

 `# Python3 program to calculate clock delay` `# Function definition with logic``def` `lagDuration(h1, m1, h2, m2, k):``    ``lag, t1, t2 ``=` `0``, ``0``, ``0``    ` `    ``# Conversion to minutes``    ``t1 ``=` `(h1 ``+` `k) ``*` `60` `+` `m1``    ` `    ``# Conversion to minutes``    ``t2 ``=` `h2 ``*` `60` `+` `m2``    ` `    ``# Calculating difference``    ``lag ``=` `t1 ``-` `t2``    ``return` `lag` `# Driver Code``h1, m1 ``=` `12``, ``0``h2, m2 ``=` `12``, ``58``k ``=` `1` `lag ``=` `lagDuration(h1, m1, h2, m2, k)``print``(``"Lag ="``, lag, ``"minutes"``)` `# This code has been contributed``# by 29AjayKumar`

## C#

 `// C# program to``// calculate clock delay``using` `System;` `class` `GFG``{` `// Function definition``// with logic``static` `int` `lagDuration(``int` `h1, ``int` `m1,``                       ``int` `h2, ``int` `m2,``                       ``int` `k)``{``    ``int` `lag, t1, t2;` `    ``// Conversion to minutes``    ``t1 = (h1 + k) * 60 + m1;` `    ``// Conversion to minutes``    ``t2 = h2 * 60 + m2;` `    ``// Calculating difference``    ``lag = t1 - t2;``    ``return` `lag;``}` `// Driver Code``public` `static` `void` `Main()``{``    ``int` `h1 = 12, m1 = 0;``    ``int` `h2 = 12, m2 = 58;``    ``int` `k = 1;` `    ``int` `lag = lagDuration(h1, m1, h2, m2, k);``    ``Console.WriteLine(``"Lag = "` `+ lag +``                      ``" minutes"``);``}``}` `// This code is contributed``// by Akanksha Rai(Abby_akku)`

## PHP

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## Javascript

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Output:

`Lag = 2 minutes`

Time Complexity: O(1)

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