Given the initial clock time h1:m1 and the present clock time h2:m2, denoting hour and minutes in 24-hours clock format. The present clock time h2:m2 may or may not be correct. Also given a variable K which denotes the number of hours passed. The task is to calculate the delay in seconds i.e. time difference between expected time and given time.
Examples :
Input: h1 = 10, m1 = 12, h2 = 10, m2 = 17, k = 2
Output: 115 minutes
The clock initially displays 10:12. After 2 hours it must show 12:12. But at this point, the clock displays 10:17. Hence, the clock must be lagging by 115 minutes. so the answer is 115.
Input: h1 = 12, m1 = 00, h2 = 12, m2 = 58, k = 1
Output: 2 minutes
The clock initially displays 12:00. After 1 hour it must show 13:00. But at this point, the clock displays 12:58. Hence, the clock must be lagging by 2 minutes. so the answer is 2.
Approach:
- Convert given time in h:m format to number of minutes. It is simply 60*h+m.
- Calculate both the computed time(adding K hours to the initial time).
- Find the difference in minutes which will be the answer.
Below is the implementation of the above approach.
C++
#include <bits/stdc++.h>
int lagDuration( int h1, int m1, int h2, int m2, int k)
{
int lag, t1, t2;
t1 = (h1 + k) * 60 + m1;
t2 = h2 * 60 + m2;
lag = t1 - t2;
return lag;
}
int main()
{
int h1 = 12, m1 = 0;
int h2 = 12, m2 = 58;
int k = 1;
int lag = lagDuration(h1, m1, h2, m2, k);
printf ( "Lag = %d minutes" , lag);
return 0;
}
|
Java
class GFG
{
static int lagDuration( int h1, int m1,
int h2, int m2,
int k)
{
int lag, t1, t2;
t1 = (h1 + k) * 60 + m1;
t2 = h2 * 60 + m2;
lag = t1 - t2;
return lag;
}
public static void main(String args[])
{
int h1 = 12 , m1 = 0 ;
int h2 = 12 , m2 = 58 ;
int k = 1 ;
int lag = lagDuration(h1, m1, h2, m2, k);
System.out.println( "Lag = " + lag +
" minutes" );
}
}
|
Python3
def lagDuration(h1, m1, h2, m2, k):
lag, t1, t2 = 0 , 0 , 0
t1 = (h1 + k) * 60 + m1
t2 = h2 * 60 + m2
lag = t1 - t2
return lag
h1, m1 = 12 , 0
h2, m2 = 12 , 58
k = 1
lag = lagDuration(h1, m1, h2, m2, k)
print ( "Lag =" , lag, "minutes" )
|
C#
using System;
class GFG
{
static int lagDuration( int h1, int m1,
int h2, int m2,
int k)
{
int lag, t1, t2;
t1 = (h1 + k) * 60 + m1;
t2 = h2 * 60 + m2;
lag = t1 - t2;
return lag;
}
public static void Main()
{
int h1 = 12, m1 = 0;
int h2 = 12, m2 = 58;
int k = 1;
int lag = lagDuration(h1, m1, h2, m2, k);
Console.WriteLine( "Lag = " + lag +
" minutes" );
}
}
|
PHP
<?php
function lagDuration( $h1 , $m1 ,
$h2 , $m2 , $k )
{
$t1 = ( $h1 + $k ) * 60 + $m1 ;
$t2 = $h2 * 60 + $m2 ;
$lag = $t1 - $t2 ;
return $lag ;
}
$h1 = 12;
$m1 = 0;
$h2 = 12;
$m2 = 58;
$k = 1;
$lag = lagDuration( $h1 , $m1 , $h2 ,
$m2 , $k );
echo "Lag = $lag minutes" ;
|
Javascript
<script>
function lagDuration(h1 , m1 , h2 , m2 , k) {
var lag, t1, t2;
t1 = (h1 + k) * 60 + m1;
t2 = h2 * 60 + m2;
lag = t1 - t2;
return lag;
}
var h1 = 12, m1 = 0;
var h2 = 12, m2 = 58;
var k = 1;
var lag = lagDuration(h1, m1, h2, m2, k);
document.write( "Lag = " + lag + " minutes" );
</script>
|
Time Complexity: O(1)
Auxiliary Space: O(1) as it is using constant space for variables
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Last Updated :
13 Mar, 2023
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