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Time Complexity where loop variable is incremented by 1, 2, 3, 4 ..
  • Difficulty Level : Easy
  • Last Updated : 30 Oct, 2015

What is the time complexity of below code?




void fun(int n)
{
   int j = 1, i = 0;
   while (i < n)
   {
       // Some O(1) task
       i = i + j;
       j++;
   }
}


The loop variable ‘i’ is incremented by 1, 2, 3, 4, … until i becomes greater than or equal to n.

The value of i is x(x+1)/2 after x iterations. So if loop runs x times, then x(x+1)/2 < n. Therefore time complexity can be written as Θ(√n).

This article is contributed by Piyush Gupta. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above

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