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The most occurring number in a string using Regex in python
  • Last Updated : 29 Dec, 2020

Given a string str, the task is to extract all the numbers from a string and find out the most occurring element of them using Regex Python.

  • It is guaranteed that no two element have the same frequency
    • Examples:

      Input :geek55of55geeks4abc3dr2 
      Output :55
      
      Input :abcd1def2high2bnasvd3vjhd44
      Output :2
      

      Approach:Extract all the numbers from a string str using re.findall() function from regex library in python, and with the use of Counter function from collection library we can get the most occurred element.

      Below is the Python implementation of above approach




      # your code goes here# Python program to 
      # find the most occurring element 
      import re 
      from collections import Counter 
        
      def most_occr_element(word):
            
          # re.findall will extract all the elements 
          # from the string and make a list
          arr = re.findall(r'[0-9]+', word)    
            
          # to store maxm frequency
          maxm = 0  
        
          # to store maxm element of most frequency
          max_elem = 0
            
          # counter will store all the number with 
          # their frequencies
          # c = counter((55, 2), (2, 1), (3, 1), (4, 1))    
          c = Counter(arr)
          
          # Store all the keys of counter in a list in
          # which first would we our required element    
          for x in list(c.keys()):
        
              if c[x]>= maxm:
                  maxm = c[x]
                  max_elem = int(x)
                        
          return max_elem
        
      # Driver program 
      if __name__ == "__main__"
          word = 'geek55of55gee4ksabc3dr2x'
          print(most_occr_element(word))

      
      

      Output:

      55
      

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