Tetracontapentagon number

A Tetracontapentagon Number is a class of figurate numbers. It has a 45 sided polygon called Tetracontapentagon. The N-th Tetracontapentagon number count’s the 45 number of dots and all other dots are surrounding with a common sharing corner and make a pattern.
First few Tetracontapentagonol Numbers are: 

1, 45, 132, 262,… 

Program to find the Nth Tetracontapentagon Number

Given a number N, the task is to find N^th Tetracontapentagon Number.
Examples:

Input: N = 2 
Output: 45 
Explanation:
The second Tetracontapentagonol number is 45. 
Input: N = 3 
Output: 132 

Approach: The N-th Tetracontapentagon Number is given by the formula: 

• N-th term of S sided polygon = 
  
• Therefore N-th term of 45 sided polygon is given by: 
  

• 
  

Below is the implementation of the above approach:

C++

// C++ program for the above approach
#include <bits/stdc++.h>
using namespace std;

// Function to find the N-th
// Tetracontapentagon Number
int TetracontapentagonNum(int N)
{
    return (43 * N * N - 41 * N)
        / 2;
}

// Driver Code
int main()
{
    // Given Number
    int N = 3;

    // Function Call
    cout << TetracontapentagonNum(N);

    return 0;
}

Java

// Java program for the above approach
class GFG{

// Function to find the nth
// TetracontapentagonNum number
static int TetracontapentagonNum(int N)
{
    return (43 * N * N - 41 * N) / 2;
}

// Driver code
public static void main(String[] args)
{
    int n = 3;
    System.out.print(TetracontapentagonNum(n));
}
}

// This code is contributed by Pratima Pandey

Python3

# Python3 program for the above approach

# Function to find the N-th
# Tetracontapentagon Number
def TetracontapentagonNum(N):

    return (43 * N * N - 41 * N) // 2;

# Driver Code

# Given Number
N = 3;

# Function Call
print(TetracontapentagonNum(N));

# This code is contributed by Code_Mech

C#

// C# program for the above approach
using System;
class GFG{

// Function to find the nth
// TetracontapentagonNum number
static int TetracontapentagonNum(int N)
{
    return (43 * N * N - 41 * N) / 2;
}

// Driver code
public static void Main()
{
    int n = 3;
    Console.Write(TetracontapentagonNum(n));
}
}

// This code is contributed by Code_Mech

Javascript

<script>

// Javascript program for the above approach


    // Function to find the nth
    // TetracontapentagonNum number
    function TetracontapentagonNum( N) {
        return (43 * N * N - 41 * N) / 2;
    }

    // Driver code

        let n = 3;
        document.write(TetracontapentagonNum(n));


// This code contributed by gauravrajput1

</script>

Output:

132