Tetracontaoctagonal Number

Given a number N, the task is to find N^th Tetracontaoctagon number.

A Tetracontaoctagon number is a class of figurate numbers. It has a 48-sided polygon called Tetracontaoctagon. The N-th Tetracontaoctagonal number count’s the 48 number of dots and all other dots are surrounding with a common sharing corner and make a pattern. The first few Tetracontaoctagonol numbers are 1, 48, 141, 280, 465, 696, …

Examples:

Input: N = 2 
Output: 48 
Explanation:
The second Tetracontaoctagonol number is 48. 
Input: N = 3 
Output: 141 

Approach: The N-th Tetracontaoctagonal number is given by the formula:

• Nth term of s sided polygon = 
  
• Therefore Nth term of 48 sided polygon is
  

• 
  

Below is the implementation of the above approach:

C++

// C++ implementation for
// above approach
#include <bits/stdc++.h>
using namespace std;

// Function to find the
// nth Tetracontaoctagonal Number
int TetracontaoctagonalNum(int n)
{
    return (46 * n * n - 44 * n) / 2;
}

// Driver Code
int main()
{
    int n = 3;
    cout << TetracontaoctagonalNum(n);

    return 0;
}

Java

// Java program for above approach
class GFG{

// Function to find the
// nth TetracontaoctagonalNum Number
static int TetracontaoctagonalNum(int n)
{
    return (46 * n * n - 44 * n) / 2;
}

// Driver code
public static void main(String[] args)
{
    int n = 3;
    System.out.print(TetracontaoctagonalNum(n));
}
}

// This code is contributed by shubham

Python3

# Python3 Cimplementation for
# above approach

# Function to find the
# nth Tetracontaoctagonal Number
def TetracontaoctagonalNum(n):

    return (46 * n * n - 44 * n) / 2;

# Driver Code
n = 3;
print(TetracontaoctagonalNum(n));

# This code is contributed by Code_Mech

C#

// C# program for above approach
using System;
class GFG{

// Function to find the
// nth TetracontaoctagonalNum Number
static int TetracontaoctagonalNum(int n)
{
    return (46 * n * n - 44 * n) / 2;
}

// Driver code
public static void Main()
{
    int n = 3;
    Console.Write(TetracontaoctagonalNum(n));
}
}

// This code is contributed by Code_Mech

Javascript

<script>

// Javascript implementation for
// above approach

// Function to find the
// nth Tetracontaoctagonal Number
function TetracontaoctagonalNum(n)
{
    return (46 * n * n - 44 * n) / 2;
}

// Driver Code
var n = 3;
document.write(TetracontaoctagonalNum(n));


</script>

Output:

141

Reference: https://en.wikipedia.org/wiki/Tetracontaoctagon