TCS Placement Paper | MCQ 1

Difficulty Level : Medium
Last Updated : 06 Aug, 2019

This is a TCS model placement paper for aptitude preparation. This placement paper will cover aptitude questions that are asked in TCS recruitment drives and also strictly follows the pattern of questions asked in TCS interviews. It is recommended to solve each one of the following questions to increase your chances of clearing TCS interview.

An exam was conducted and the following was analyzed. 4 men were able to check some exam papers in 8 days working 5 hours regularly. What is the total number of hours taken by 2 men in 20 days to check double the number of exam papers?
```
Answer: 8 hours
```
Solution:

Assuming that 1 unit of work is done in 1 hour
Let’s calculate the total number of working hours:
=> 4 * 8 * 5 = 160 units
Now the work is doubled:
=> 160 * 2 = 320 units
Let ‘x’ be the number of hours taken by 2 men to complete the work in 20 days.
Therefore,
=> 2 * 20 * x = 320
=> x = 8 hours (Answer).
The numbers from 101 to 150 are written as, 101102103104105…146147148149150. What will be the remainder when this total number is divided by 3?
```
Answer: 2
```
Solution:

The divisibility rule for 3 is that the sum of all digits of a number should be divisible by 3. Let’s calculate the sum of the digits:
There are 50 1’s (unit place) = 50
There are 10 1’s (tens place) = 10
There are 10 2’s (tens place) = 20
There are 10 3’s (tens place) = 30
There are 10 4’s (tens place) = 40
There is one 5 (tens place) = 5
For each number 1 to 9, there are 5 sets of sum 45(1+2+…+9) = 225
=> So sum of all digits = 380
=> 380 / 3 = 2 (Answer)
If the alphabets are written in the sequence of a, bb, ccc, dddd, eeeee, ffffff, …. What will be the 120th letter?
```
Answer: O
```
Solution:

It can be seen that the letter are in AP sequence, So applying the formula we get,
$n(n+1)/2 <= 120$
We find that n = 15 fits the equation
The 15th letter in the English alphabet = O
So 15th term contains O.
There is a tank whose 1/7 th part is filled with fuel. If 22 liters of fuel is poured into the tank, the indicator rises to 1/5 th mark of the tank. So what is the total capacity of the tank?
```
Answer: 385
```
Solution:

Let the total capacity of the tank be ‘x’ liters.
According to the question,
=> x/7 + 22 = x/5
=> x/5 – x/7 = 22
=> x = 385 litres(Answer)
How many prime numbers lie between 3 and 100 (excluding the values) that satisfies the condition:
```
Answer: 2
```
Solution:

There are 23 prime numbers between 3 and 100 (excluding the values) of which all are odd.
For 5y – 1 to be odd, 5y must be even
For 5y to be even y should be even.
Taking y as 2 we get 5y – 1 as 9.
Now looking at all those prime numbers ending at 9 = 9, 19, 29, 39, 59, 79, 89
Out of these, the numbers satisfying both the equations(integer is assumed) are 9, 29 and 89.
We cannot consider 9 as it violates the constraint of number should be greater than 3.
Therefore answer is 2 (29 and 89)
In the given figure, find the ratio of area of the square to area of the triangle:

a) 3:2
b) 2:3
c) 2:1
d) 1:2
```
Answer: c) 2:1
```
Solution:

Let the side of the square be ‘2’ units
Area of the square = (side)^2 = $2^2$ = 4 unit
Side of triangle, using Pythagoras Theorem = $\sqrt{5}$ unit
Height of triangle = side of square (Using Pythgorean theorem)
Area of triangle = 1/2 * base * height
here, base = height = side
Area of triangle = 1/2 * (side)^2
=> 1/2 *2 * 2
=> 2 units
Therefore the ratio = 4:2
=> 2:1 (Answer)
There is a fairy island where lives a Knight, a Knave, and a Spy. You go there and meet three people suppose A, B, and C, one of whom is a knight, one a knave, and one a spy. It is known that the knight always tells the truth, the knave always lies, and the spy can either lie or tell the truth.
So who is the knight, who the knave, and who the spy?
```
Answer: A = Knight, B = Spy, C = Knave
```
Solution:

Let us say A is the Knight, then he speaks the truth and C is Knave who lied and finally B is Knave, who speaks the truth regarding A. So this condition holds.
Let us say B is the knight. then it contradicts the answer since a knight always speaks the truth and there cannot be two knights.
Same goes with C.
Find the number of perfect squares in the given series 2013, 2020, 2027, ……………., 2300? (Hint 44^2=1936)
a) 2
b) 1
c) 3
d) None of the above
```
Answer: b) 1
```
Solution:

We can see that the series is in the form of AP with common difference of 7.
So the series is in the form of 2013 + 7d
The hint is actually a shortcut:
44^2 = 1936
45^2 = 2025
46^2 = 2116
47^2 = 2209
48^2 = 2304
Therefore among these numbers, we need to find which of them are in the form of 2013 + 7d
Only one number 2209 can be written in the form 2013 + 7*28.
Therefore the answer is 1.
In the series of 7^1+7^2+7^3+7^4…….+7^204+7^205, how many numbers are there with the unit place as 3?
```
Answer: 51
```
Solution: According to the cyclicity of 7, the unit digit follows the pattern of 7, 9, 3, 1 and this repeats. So in every 4 numbers, we get one 3 in the unit place. Dividing 205 by 4 we get 51 which is the answer to the following question.
Find the number of divisors of 1728(including 1 and the number itself).
```
Answer: 28
```
Solution:

There is a direct formula for this:
Number = $p^a.q^b.r^c...$
where p, q and r are prime numbers. Simply we need to prime factorize the Number.
Then, (a+1).(b+1).(c+1) is the number of divisors.
For 1728 = $2^6.3^3$
Therfore, (6+1).(3+1) = 28

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