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# sympy.stats.Levy() in python

• Last Updated : 05 Jun, 2020

With the help of `sympy.stats.Levy()` method, we can get the continuous random variable which represents the levy distribution.

Syntax : `sympy.stats.Levy(name, mu, c)`
Where, mu and c are real number and mu, c > 0.
Return : Return the continuous random variable.

Example #1 :
In this example we can see that by using `sympy.stats.Levy()` method, we are able to get the continuous random variable representing levy distribution by using this method.

 `# Import sympy and Levy``from` `sympy.stats ``import` `Levy, density``from` `sympy ``import` `Symbol, pprint`` ` `z ``=` `Symbol(``"z"``)``mu ``=` `Symbol(``"mu"``, positive ``=` `True``)``c ``=` `Symbol(``"c"``, positive ``=` `True``)`` ` `# Using sympy.stats.Levy() method``X ``=` `Levy(``"x"``, mu, c)``gfg ``=` `density(X)(z)`` ` `pprint(gfg)`

Output :

sqrt(2)*sqrt(c)*exp(-c/(-2*mu + 2*z))/(2*sqrt(pi)*(-mu + z)**(3/2))

Example #2 :

 `# Import sympy and Levy``from` `sympy.stats ``import` `Levy, density``from` `sympy ``import` `Symbol, pprint`` ` `z ``=` `0.3``mu ``=` `3``c ``=` `2`` ` `# Using sympy.stats.Levy() method``X ``=` `Levy(``"x"``, mu, c)``gfg ``=` `density(X)(z)`` ` `pprint(gfg)`

Output :

0.014240812169263

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