sympy.stats.Levy() in python
With the help of sympy.stats.Levy()
method, we can get the continuous random variable which represents the levy distribution.
Syntax : sympy.stats.Levy(name, mu, c)
Where, mu and c are real number and mu, c > 0.
Return : Return the continuous random variable.
Example #1 :
In this example we can see that by using sympy.stats.Levy()
method, we are able to get the continuous random variable representing levy distribution by using this method.
from sympy.stats import Levy, density
from sympy import Symbol, pprint
z = Symbol( "z" )
mu = Symbol( "mu" , positive = True )
c = Symbol( "c" , positive = True )
X = Levy( "x" , mu, c)
gfg = density(X)(z)
pprint(gfg)
|
Output :
sqrt(2)*sqrt(c)*exp(-c/(-2*mu + 2*z))/(2*sqrt(pi)*(-mu + z)**(3/2))
Example #2 :
from sympy.stats import Levy, density
from sympy import Symbol, pprint
z = 0.3
mu = 3
c = 2
X = Levy( "x" , mu, c)
gfg = density(X)(z)
pprint(gfg)
|
Output :
0.014240812169263
Last Updated :
05 Jun, 2020
Like Article
Save Article
Share your thoughts in the comments
Please Login to comment...