SymPy | Permutation.order() in Python
Permutation.order() : order() is a sympy Python library function that calculates the order of a permutation. When the permutation is raised to the power of its order, then, in that case, the order equals the identity permutation.
Syntax : sympy.combinatorics.permutations.Permutation.order()
Return : order of the permutation
Code #1 : order() Example
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
a = Permutation([[ 2 , 0 ], [ 3 , 1 ]])
b = Permutation([ 1 , 3 , 5 , 4 , 2 , 0 ])
print ( "Permutation a - order form : " , a.order())
print ( "Permutation b - order form : " , b.order())
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Output :
Permutation a – order form : 2
Permutation b – order form : 6
Code #2 : order() Example – 2D Permutation
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
a = Permutation([[ 2 , 4 , 0 ],
[ 3 , 1 , 2 ],
[ 1 , 5 , 6 ]])
print ( "Permutation a - order form : " , a.order())
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Output :
Permutation a – order form : 7
Last Updated :
27 Aug, 2019
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