# SymPy | Permutation.order() in Python

Permutation.order() : order() is a sympy Python library function that calculates the order of a permutation. When the permutation is raised to the power of its order, then, in that case, the order equals the identity permutation.

Syntax : sympy.combinatorics.permutations.Permutation.order()

Return : order of the permutation

Code #1 : order() Example

 `# Python code explaining ` `# SymPy.Permutation.order() ` ` `  `# importing SymPy libraries ` `from` `sympy.combinatorics.partitions ``import` `Partition ` `from` `sympy.combinatorics.permutations ``import` `Permutation ` ` `  `# Using from sympy.combinatorics.permutations.Permutation.order() method  ` ` `  `# creating Permutation ` `a ``=` `Permutation([[``2``, ``0``], [``3``, ``1``]]) ` ` `  `b ``=` `Permutation([``1``, ``3``, ``5``, ``4``, ``2``, ``0``]) ` ` `  ` `  `print` `(``"Permutation a - order form : "``, a.order()) ` `print` `(``"Permutation b - order form : "``, b.order()) `

Output :

Permutation a – order form : 2
Permutation b – order form : 6

Code #2 : order() Example – 2D Permutation

 `# Python code explaining ` `# SymPy.Permutation.order() ` ` `  `# importing SymPy libraries ` `from` `sympy.combinatorics.partitions ``import` `Partition ` `from` `sympy.combinatorics.permutations ``import` `Permutation ` ` `  `# Using from sympy.combinatorics.permutations.Permutation.order() method  ` ` `  `# creating Permutation ` `a ``=` `Permutation([[``2``, ``4``, ``0``],  ` `                 ``[``3``, ``1``, ``2``], ` `                 ``[``1``, ``5``, ``6``]]) ` ` `  ` `  `print` `(``"Permutation a - order form : "``, a.order()) `

Output :

Permutation a – order form : 7

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