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SymPy | Permutation.order() in Python

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Permutation.order() : order() is a sympy Python library function that calculates the order of a permutation. When the permutation is raised to the power of its order, then, in that case, the order equals the identity permutation.

Syntax : sympy.combinatorics.permutations.Permutation.order()

Return : order of the permutation

Code #1 : order() Example




# Python code explaining
# SymPy.Permutation.order()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.order() method 
  
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
  
b = Permutation([1, 3, 5, 4, 2, 0])
  
  
print ("Permutation a - order form : ", a.order())
print ("Permutation b - order form : ", b.order())


Output :

Permutation a – order form : 2
Permutation b – order form : 6

Code #2 : order() Example – 2D Permutation




# Python code explaining
# SymPy.Permutation.order()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.order() method 
  
# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])
  
  
print ("Permutation a - order form : ", a.order())


Output :

Permutation a – order form : 7



Last Updated : 27 Aug, 2019
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