Swap all the pair of bits in a byte. Before swapping: 11-10-11-01 After swapping: 11-01-11-10
Input : 00000010 Output : 00000001 Input : 00000100 Output : 00001000
x = ((x & 0b10101010) >> 1) | ((x & 0b01010101) <> 1 extracts the high bit position and shifts it to the low bit position.
Similarly the expression (x & 0b01010101) << 1 extracts the low bit from each pair and shifts it to the high bit position.
The two parts are then combined using bitwise-OR.
x= 00011010 ((x & 0b10101010) >> 1) = 00001010 >> 1 = 00000101 ((x & 0b01010101) << 1) = 00010000 <> 1) | ((x & 0b01010101) << 1) = 00100101
Below is the implementation of the above:
Note: This solution works for only 8 bit.
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Improved By : Mithun Kumar