Sum of the series 0.6, 0.06, 0.006, 0.0006, …to n terms
Given the number of terms i.e. n. Find the sum of the series 0.6, 0.06, 0.006, 0.0006, …to n terms.
Examples:
Input : 2 Output : 0.65934 Input : 3 Output : 0.665334
Lets denote the sum by S:
Using the formula , we have [since r<1]
Hence the required sum is
Below is the implementation:
C++
// CPP program to find sum of 0.6, 0.06, // 0.006, 0.0006, ...to n terms #include <bits/stdc++.h> using namespace std; // function which return the // the sum of series float sumOfSeries( int n) { return (0.666) * (1 - 1 / pow (10, n)); } // Driver code int main() { int n = 2; cout << sumOfSeries(n); } |
Java
// java program to find sum of 0.6, 0.06, // 0.006, 0.0006, ...to n terms import java.io.*; class GFG { // function which return the // the sum of series static double sumOfSeries( int n) { return ( 0.666 ) * ( 1 - 1 /Math. pow( 10 , n)); } // Driver code public static void main (String[] args) { int n = 2 ; System.out.println ( sumOfSeries(n)); } } // This code is contributed by vt_m |
Python3
# Python3 program to find # sum of 0.6, 0.06, 0.006, # 0.0006, ...to n terms import math # function which return # the sum of series def sumOfSeries(n): return (( 0.666 ) * ( 1 - 1 / pow ( 10 , n))); # Driver code n = 2 ; print (sumOfSeries(n)); # This code is contributed by mits |
C#
// C# program to find sum of 0.6, 0.06, // 0.006, 0.0006, ...to n terms using System; class GFG { // function which return the // the sum of series static double sumOfSeries( int n) { return (0.666) * (1 - 1 /Math. Pow(10, n)); } // Driver code public static void Main () { int n = 2; Console.WriteLine( sumOfSeries(n)); } } // This code is contributed by vt_m |
PHP
<?php // PHP program to find sum of 0.6, 0.06, // 0.006, 0.0006, ...to n terms // function which return the // the sum of series function sumOfSeries( $n ) { return (0.666) * (1 - 1 / pow(10, $n )); } // Driver code $n = 2; echo (sumOfSeries( $n )); // This code is contributed by Ajit. ?> |
Javascript
<script> // javascript program to find sum of 0.6, 0.06, // 0.006, 0.0006, ...to n terms // function which return the // the sum of series function sumOfSeries( n) { return (0.666) * (1 - 1 / Math.pow(10, n)); } // Driver Code let n = 2 ; document.write(sumOfSeries(n).toFixed(5)) ; // This code is contributed by aashish1995 </script> |
Output:
0.65934