Given the area of three faces of the rectangular **parallelepiped** which has a common vertex. Our task is to find the **sum of lengths of all 12 edges** of this parallelepiped.

In geometry, a parallelepiped is a three-dimensional figure formed by six parallelograms. By analogy, it relates to a parallelogram just as a cube relates to a square or as a cuboid to a rectangle. A picture of a rectangular parallelepiped is shown below.

**Examples:**

Input:1 1 1Output:12Input:20 10 50Output:68

**Approach:** The area given are s1, s2 and s3 . Let a, b and c be the lengths of the sides that have one common vertex. Where , , . It’s easy to find the length in terms of faces areas: , , . The answer will be the summation of all the 4 sides, there are four sides that have lengths equal to a, b and c.

In the first example the given area s1 = 1, s2 = 1 and s3 = 1. So with the above approach, the value of a, b, c will come out to be 1. So the sum of the length of all 12 edges will be 4 * 3 = 12.

Below is the implementation of the above approach:

## C++

`// C++ program to illustrate` `// the above problem` `#include <bits/stdc++.h>` `using` `namespace` `std;` ` ` `// function to find the sum of` `// all the edges of parallelepiped` `double` `findEdges(` `double` `s1, ` `double` `s2, ` `double` `s3)` `{` ` ` `// to calculate the length of one edge` ` ` `double` `a = ` `sqrt` `(s1 * s2 / s3);` ` ` `double` `b = ` `sqrt` `(s3 * s1 / s2);` ` ` `double` `c = ` `sqrt` `(s3 * s2 / s1);` ` ` ` ` `// sum of all the edges of one side` ` ` `double` `sum = a + b + c;` ` ` ` ` `// net sum will be equal to the` ` ` `// summation of edges of all the sides` ` ` `return` `4 * sum;` `}` ` ` `// Driver code` `int` `main()` `{` ` ` `// initialize the area of three` ` ` `// faces which has a common vertex` ` ` `double` `s1, s2, s3;` ` ` `s1 = 65, s2 = 156, s3 = 60;` ` ` ` ` `cout << findEdges(s1, s2, s3);` ` ` ` ` `return` `0;` `}` |

## Java

`// Java program to illustrate` `// the above problem` ` ` `import` `java.io.*;` ` ` `class` `GFG {` ` ` `// function to find the sum of` `// all the edges of parallelepiped` `static` `double` `findEdges(` `double` `s1, ` `double` `s2, ` `double` `s3)` `{` ` ` `// to calculate the length of one edge` ` ` `double` `a = Math.sqrt(s1 * s2 / s3);` ` ` `double` `b = Math.sqrt(s3 * s1 / s2);` ` ` `double` `c = Math.sqrt(s3 * s2 / s1);` ` ` ` ` `// sum of all the edges of one side` ` ` `double` `sum = a + b + c;` ` ` ` ` `// net sum will be equal to the` ` ` `// summation of edges of all the sides` ` ` `return` `4` `* sum;` `}` ` ` ` ` `// Driver code` ` ` ` ` `public` `static` `void` `main (String[] args) {` ` ` `// initialize the area of three` ` ` `// faces which has a common vertex` ` ` `double` `s1, s2, s3;` ` ` `s1 = ` `65` `; s2 = ` `156` `; s3 = ` `60` `;` ` ` ` ` `System.out.print(findEdges(s1, s2, s3));` ` ` `}` `}` ` ` ` ` `// this code is contributed by anuj_67..` |

## Python3

`import` `math` ` ` `# Python3 program to illustrate` `# the above problem` ` ` `# function to find the sum of` `# all the edges of parallelepiped` `def` `findEdges(s1, s2, s3):` ` ` ` ` `# to calculate the length of one edge` ` ` `a ` `=` `math.sqrt(s1 ` `*` `s2 ` `/` `s3)` ` ` `b ` `=` `math.sqrt(s3 ` `*` `s1 ` `/` `s2)` ` ` `c ` `=` `math.sqrt(s3 ` `*` `s2 ` `/` `s1)` ` ` ` ` `# sum of all the edges of one side` ` ` `sum` `=` `a ` `+` `b ` `+` `c` ` ` ` ` `# net sum will be equal to the` ` ` `# summation of edges of all the sides` ` ` `return` `4` `*` `sum` ` ` ` ` `# Driver code` `if` `__name__` `=` `=` `'__main__'` `:` ` ` `# initialize the area of three` `# faces which has a common vertex` ` ` `s1 ` `=` `65` ` ` `s2 ` `=` `156` ` ` `s3 ` `=` `60` ` ` ` ` `print` `(` `int` `(findEdges(s1, s2, s3)))` ` ` `# This code is contributed by ` `# Shivi_Aggarwal` |

## C#

`// C# program to illustrate` `// the above problem` `using` `System;` ` ` `public` `class` `GFG{` ` ` `// function to find the sum of` `// all the edges of parallelepiped` `static` `double` `findEdges(` `double` `s1, ` `double` `s2, ` `double` `s3)` `{` ` ` `// to calculate the length of one edge` ` ` `double` `a = Math.Sqrt(s1 * s2 / s3);` ` ` `double` `b = Math.Sqrt(s3 * s1 / s2);` ` ` `double` `c = Math.Sqrt(s3 * s2 / s1);` ` ` ` ` `// sum of all the edges of one side` ` ` `double` `sum = a + b + c;` ` ` ` ` `// net sum will be equal to the` ` ` `// summation of edges of all the sides` ` ` `return` `4 * sum;` `}` ` ` `// Driver code` ` ` ` ` `static` `public` `void` `Main (){` ` ` `// initialize the area of three` ` ` `// faces which has a common vertex` ` ` `double` `s1, s2, s3;` ` ` `s1 = 65; s2 = 156; s3 = 60;` ` ` ` ` `Console.WriteLine(findEdges(s1, s2, s3));` ` ` `}` `}` ` ` ` ` `// This code is contributed by anuj_67..` |

## PHP

`<?php` `// PHP program to illustrate` `// the above problem` ` ` `// function to find the sum of` `// all the edges of parallelepiped` `function` `findEdges(` `$s1` `, ` `$s2` `, ` `$s3` `)` `{` ` ` `// to calculate the length of one edge` ` ` `$a` `= sqrt(` `$s1` `* ` `$s2` `/ ` `$s3` `);` ` ` `$b` `= sqrt(` `$s3` `* ` `$s1` `/ ` `$s2` `);` ` ` `$c` `= sqrt(` `$s3` `* ` `$s2` `/ ` `$s1` `);` ` ` ` ` `// sum of all the edges of one side` ` ` `$sum` `= ` `$a` `+ ` `$b` `+ ` `$c` `;` ` ` ` ` `// net sum will be equal to the` ` ` `// summation of edges of all the sides` ` ` `return` `4 * ` `$sum` `;` `}` ` ` `// Driver code` ` ` `// initialize the area of three` `// faces which has a common vertex` `$s1` `; ` `$s2` `; ` `$s3` `;` `$s1` `= 65; ` `$s2` `= 156; ` `$s3` `= 60;` ` ` `echo` `findEdges(` `$s1` `, ` `$s2` `, ` `$s3` `);` ` ` `// This code is contributed by Shashank` `?>` |

**Output:**

120

**Reference:** https://en.wikipedia.org/wiki/Parallelepiped

Attention reader! Don’t stop learning now. Get hold of all the important mathematical concepts for competitive programming with the **Essential Maths for CP Course** at a student-friendly price. To complete your preparation from learning a language to DS Algo and many more, please refer **Complete Interview Preparation Course****.**