# Sum of array using pointer arithmetic

• Difficulty Level : Easy
• Last Updated : 26 Dec, 2017

Given an array, write a program to find the sum of array using pointers arithmetic.

In this program we make use of * operator . The * (asterisk) operator denotes the value of variable. The * operator at the time of declaration denotes that this is a pointer, otherwise it denotes the value of the memory location pointed by the pointer .
sum() function is used to find the sum of the array through pointers.

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Examples :

```Input : array = 2, 4, -6, 5, 8, -1
Output : sum = 12

Input :  array = 1, 4, -6, 8, -10, -12
Output : sum = -15
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

 `// CPP program to find sum of array using pointers``#include ``using` `namespace` `std;`` ` `// Function to find the sum of the array``void` `sum(``int``* array, ``int` `length)``{``    ``int` `i, sum_of_array = 0;``    ``for` `(i = 0; i < length; i++)``        ``sum_of_array = sum_of_array + *(array + i);``    ``cout << ``"sum of array is = "` `<< sum_of_array;``}``// Driver function``int` `main()``{``    ``// Array to hold the values``    ``int` `array[] = { 2, 4, -6, 5, 8, -1 };``    ``sum(array, 6);``    ``return` `0;``}`

Output :

```sum of array is = 12
```
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