Sum of array using pointer arithmetic
Given an array, write a program to find the sum of array using pointers arithmetic.
In this program we make use of * operator . The * (asterisk) operator denotes the value of variable. The * operator at the time of declaration denotes that this is a pointer, otherwise it denotes the value of the memory location pointed by the pointer .
sum() function is used to find the sum of the array through pointers.
Examples :
Input : array = 2, 4, -6, 5, 8, -1 Output : sum = 12 Input : array = 1, 4, -6, 8, -10, -12 Output : sum = -15
// CPP program to find sum of array using pointers#include <iostream>using namespace std; // Function to find the sum of the arrayvoid sum(int* array, int length){ int i, sum_of_array = 0; for (i = 0; i < length; i++) sum_of_array = sum_of_array + *(array + i); cout << "sum of array is = " << sum_of_array;}// Driver functionint main(){ // Array to hold the values int array[] = { 2, 4, -6, 5, 8, -1 }; sum(array, 6); return 0;} |
Output :
sum of array is = 12
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