Given two arrays of integers where maximum size of first array is big and that of second array is small. Your task is to find if there is a pair in the first array whose sum is present in the second array.
Input: 4 1 5 10 8 3 2 20 13 Output: 1
Approach : We have x + y = z. This can be rewritten as x = z – y. This means, we need to find an element x in array 1 such that it is the result of z(second array) – y(first array). For this, use hashing to keep track of such element x.
- Sudo Placement | Placement Tour
- Check if the array is beautiful
- Sudo Placement[1.4] | K Sum
- Sudo Placement[1.4] | BST Traversal
- Sudo Placement[1.5] | Wolfish
- Sudo Placement[1.5] | Partition
- Sudo Placement[1.3] | Playing with Stacks
- Sudo Placement[1.3] | Stack Design
- Sudo Placement 2 | Matrix Series
- Sudo Placement[1.3] | Final Destination
- Sudo Placement[1.4] | Jumping the Subtree
- Sudo Placement[1.5] | Second Smallest in Range
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