strxfrm() in C/C++
The c/c++ library strxfrm() transform the characters of source string into current locale and place them in destination string.
For that LC_COLLATE category is used which is defined in locale.h . strxfrm() function performs transformation in such a way that result of strcmp on two strings is the same as result of strcoll on two original strings.
Syntax:
size_t strxfrm(char *str1, const char *str2, size_t num); parameters: str1 :is the string which receives num characters of transformed string. str2 : is the string which is to be transformed num :is the maximum number of characters which to be copied into str1.
Examples :
Input : 'geeksforgeeks' Output : 13
// C program to demonstrate// strxfrm()#include <stdio.h>#include <string.h>int main(){ char src[10], dest[10]; int len; strcpy(src, "geeksforgeeks"); len = strxfrm(dest, src, 10); printf("Length of string %s is: %d", dest, len); return (0);} |
OUTPUT:
Length of string geeksforgeeks is: 13
Example 2 :
Input : 'hello geeksforgeeks' Output : 20 // in this example it count space also
// C program to demonstrate// strxfrm()#include <stdio.h>#include <string.h>int main(){ char src[20], dest[200]; int len; strcpy(src, " hello geeksforgeeks"); len = strxfrm(dest, src, 20); printf("Length of string %s is: %d", dest, len); return (0);} |
OUTPUT:
Length of string hello geeksforgeeks is: 20
Example 3 :
// C program to demonstrate// strxfrm()#include <iostream>#include <string.h>using namespace std;int main(){ char str2[30] = "Hello geeksforgeeks"; char str1[30]; cout << strxfrm(str1, str2, 4) << endl; cout << str1 << endl; cout << str2 << endl; return 0;} |
OUTPUT:
19 Hell Hello geeksforgeeks
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