strxfrm() in C/C++

The c/c++ library strxfrm() transform the characters of source string into current locale and place them in destination string.
For that LC_COLLATE category is used which is defined in locale.h . strxfrm() function performs transformation in such a way that result of strcmp on two strings is the same as result of strcoll on two original strings.
Syntax:

size_t strxfrm(char *str1, const char *str2, size_t num);
parameters:
str1 :is the string which receives 
num characters of transformed string. 
str2 : is the string which is to be transformed
num  :is the maximum number of characters
which to be copied into str1.

Examples :

Input : 'geeksforgeeks'
Output : 13

// C program to demonstrate
// strxfrm()
#include <stdio.h>
#include <string.h>
int main()
{
    char src[10], dest[10];
    int len;
    strcpy(src, "geeksforgeeks");
    len = strxfrm(dest, src, 10);
    printf("Length of string %s is: %d", dest, len);

    return (0);
}

OUTPUT:

Length of string geeksforgeeks is: 13

Example 2 :

Input : 'hello geeksforgeeks'
Output : 20 // in this example it count space also 

// C program to demonstrate
// strxfrm()
#include <stdio.h>
#include <string.h>
int main()
{
    char src[20], dest[200];
    int len;
    strcpy(src, " hello geeksforgeeks");
    len = strxfrm(dest, src, 20);
    printf("Length of string %s is: %d", dest, len);

    return (0);
}

OUTPUT:

Length of string  hello geeksforgeeks is: 20

Example 3 :

// C program to demonstrate
// strxfrm()
#include <iostream>
#include <string.h>
using namespace std;
int main()
{
    char str2[30] = "Hello geeksforgeeks";
    char str1[30];
    cout << strxfrm(str1, str2, 4) << endl;
    cout << str1 << endl;
    cout << str2 << endl;
    return 0;
}

OUTPUT:

19
Hell
Hello geeksforgeeks

This article is contributed by Shivani Baghel . If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.