Given N and K, print a string that has n characters. The string should have exactly k distinct characters and no adjacent positions.
Input : n = 5, k = 3 Output : abcab Explanation: 3 distinct character a, b, c and n length string. Input: 3 2 Output: aba Explanation: 2 distinct character 'a' and 'b' and n length string.
Consider the first k Latin letters. We will add them to the answer in the order, firstly, we add a, then b and so on. If letters are finished but the length of the answer is still less than the required one, then we start again adding letters from the beginning of the alphabet. We repeat this process until the length of the answer becomes n and print it once done.
Below is the implementation of the above approach
# Python 3 program to construct a n
# length string with k distinct characters
# such that no two same characters are adjacent.
# Function to find a string of length
# n with k distinct characters.
def findString(n, k):
# Initialize result with first k
# Latin letters
res = “”
for i in range(k):
res = res + chr(ord(‘a’) + i)
# Fill remaining n-k letters by
# repeating k letters again and again.
count = 0
for i in range(n – k) :
res = res + chr(ord(‘a’) + count)
count += 1
if (count == k):
count = 0;
# Driver code
if __name__ == “__main__”:
n = 5
k = 2
# This code is contributed by ita_c
Time complexity : O(n)
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